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3 years ago

To find a power series for the function, centered at 0. f(x) = 18 (x + 1)3

Mathematics

1 answer:

schepotkina [342]3 years ago

5 0

Consider this option; make a design according to the local requirements.

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What dimension is a single point?

mestny [16]

A point has D) zero dimensions

4 0

3 years ago

Three consecutive even integers have a sum of 36 . Find the integers.

Sonbull [250]

Try the different integers together:
6 + 7 + 8 = 21
8 + 9 + 10 = 27

Keep trying a few digits up and you should get the answer soon.

4 0

3 years ago

QUESTION 5

Anna [14]

Answer:

$P\cup Q=\{1,\ 2,\ 3,\ 4,\ 5,\ 7,\ 8,\ 9, \ 10,\ 11\}$

Step-by-step explanation:

The union of two sets P and Q, denoted as $P\cup Q,$ is the set of all elements that are in the set P or in the set Q or in both sets P and Q.

Given:

P = {7, 8, 9, 10, 11}

Q = {1, 2, 3, 4, 5}

Then

$P\cup Q=\{1,\ 2,\ 3,\ 4,\ 5,\ 7,\ 8,\ 9, \ 10,\ 11\}$

When writing the union set, simply write all elements from both sets in on set.

4 0

4 years ago

The length of a rectangle is 3 times its width. If the length were increased by 2 inches and the width by 1 inch, the new perime

Dennis_Churaev [7]

Pretty sure it’s the second option because length would be 3w+2
and width would be w+1 and with area you have to multiply so it would just be the (w+1)(3w+2)

5 0

3 years ago

Read 2 more answers

Reduced form of 2ab^2-a^2 b^2/5

Ket [755]

Answer:

$2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}$

Step-by-step explanation:

Given the expression

$2ab^2-\frac{a^2b^2}{5}$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}$

$2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{2ab^2\cdot \:5-a^2b^2}{5}$

$=\frac{10ab^2-a^2b^2}{5}$

Thus,

$2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}$

7 0

3 years ago