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iren [92.7K]
4 years ago
13

PLEASE HELP QUICKLY!!

Mathematics
2 answers:
Effectus [21]4 years ago
8 0

Answer:

X int: (-3,0)

y int: (0,-6)

Step-by-step explanation:


xxMikexx [17]4 years ago
6 0

y =-2x-6

y =-2(x+3)

the x intercept is -3

the y intercept is -6

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. Describe a way you can use graham crackers to demonstrate the division problem . Include the result in your description.
Digiron [165]

Answer:

You can split your cracker 4 ways. So each cracker is  now 4. Now split your cracker into 4ths, 5•4 = 20! Hope this helps!

Step-by-step explanation:

Your Crackers have those lines, and they split 4 ways. SO this helps make the problem easierto solve.


6 0
4 years ago
Pls help me answer this! <br> I tried to answer it but i don’t get it. Thx y’all so much!
True [87]
Left 7 units and right 3 units
5 0
3 years ago
Read 2 more answers
A circle has a diameter of 26 feet. Find its circumference and area.
iogann1982 [59]

Answer: 81.64 feet

Step-by-step explanation:

Circumference of a circle = pi * diameter

Circumference of a circle = 3.14 * 26 feet

Circumference of a circle = 81.64 feet

5 0
2 years ago
Someone please help I don’t understand this please
sdas [7]

The fraction of the image in blue with respect to the <em>entire</em> hexagon is \frac{1}{3}.

<h3>Estimation of the ratio of the shaded region area to the entire area</h3>

Initially we proceed to create auxiliar constructions , represented by red line segments, to re-define the hexagon as a sum of standard figures. According to the figure, we find two types of triangles (type-1 and type-2), and the following relationship between the two types:

A_{1} = A_{2} (1)

Where:

  • A_{1} - Area of a type-1 triangle.
  • A_{2} - Area of a type-2 triangle.

The formulae for the area of the shaded region (A_{s}) and the <em>entire</em> hexagon (A_{h}) are, respectively:

<h3>Shaded region</h3>

A_{s} = 2\cdot A_{1} + 4\cdot A_{2} (2)

<h3>Entire hexagon</h3>

A_{h} = 8\cdot A_{1} + 10\cdot A_{2} (3)

And the fraction of the image in blue is:

\frac{A_{s}}{A_{h}} =  \frac{2\cdot A_{1}+4\cdot A_{2}}{8\cdot A_{1}+10\cdot A_{2}}

\frac{A_{s}}{A_{h}} = \frac{6\cdot A}{18\cdot A}

\frac{A_{s}}{A_{h}} = \frac{1}{3}

The fraction of the image in blue with respect to the <em>entire</em> hexagon is \frac{1}{3}. \blacksquare

To learn more on hexagons, we kindly invite to check this verified question: brainly.com/question/4083236

6 0
3 years ago
Solve the system of equations and choose the correct ordered pair 4x - 2y + 7 =33 and 5y=3x-30
Kay [80]
1. Solve for x in 4x-2y+7=33
4x-2y+7=33
4x+6=33+2y
4x=33+2y-7
4x=2y+26
x=(2y+26)/4
x=(2(y+13))/4
x=(y+13)/2

2. Substitute x=(y+13)/2 into 5y=3x-30
5y=3x-30
5y=3*(y+13)/2 -30
5y=(3(y+13))/2 - 30

3. Solve for y in 5y=(3(y+13)/2 -30
5y=(3(y+13))/2 - 30
10y=3(y+13)-60
10y=3y+39-60
10y=3y-21
10y-3y=-21
7y=-21
y=-21/7
y=-3

4. Substitute y=-3 into x=(y+13)/2
x=(y+13)/2
x=(-3+13)/2
x=5

5. Therefore, 
x=5 and y=-3

I hope you have a nice day :D
4 0
3 years ago
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