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3 years ago

What is 1+1? I wonder if anyone would answer this cause no one seems to see my questions

Mathematics

2 answers:

stealth61 [152]3 years ago

7 0

Your answer is gonna be two

victus00 [196]3 years ago

7 0

The answer to 1+1 is 2

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Solve the equation using the quadratic formula.

gayaneshka [121]

The last one is the answer

5 0

3 years ago

Read 2 more answers

The distance on a numberline from -10 to 3 is equal to 5x-12.

Viefleur [7K]

Answer:

13
x = 5

Step-by-step explanation:

To find the total distance, we can add.

10 + 3 = 13

Now, we can use 13 to solve for the equation that is the same.

5x - 12 = 13

5x = 25

x = 5

Best of Luck!

6 0

3 years ago

Jimmy Andrew and Richard collect comic books. Jimmy has five more comic books than Andrew, and Richard has four times as many co

adell [148]

Answer: Andrew = 20

Jimmy = 25

Richard = 100

Step-by-step explanation:

Let the number of Andrew's comic books be y.

Jimmy has five more comic books than Andrew. This means Jimmy has: y+5

Richard has four times as many comic book as jimmy. This means Richard has: 4(y+5) = 4y + 20

Since there are 145 comic books together. This can be rewritten as:

y + (y+5) + (4y+20) = 145

6y+25 = 145

6y = 145 - 25

y = 120/6

y = 20

Andrew has 20 comic books

Jimmy has five more comic books than Andrew. Jimmy has: 20+5 = 25

Richard has: 4y + 20 = 4(20) + 20 = 100

5 0

3 years ago

Write the equation of a line that passes through the points ( 2 , - 5 ) and ( 8 , - 2 )

kati45 [8]

Answer:

$y=\frac{1}{2}x-6$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

<u>1) Determine the slope (m)</u>

$m=\frac{y_2-y_1}{x_2-x_1}$ where two points that fall on the line are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (2,-5) and (8,-2)

$m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{-2-(-5)}{8-2}\\=\frac{-2+5}{8-2}\\=\frac{3}{6}\\=\frac{1}{2}$

Therefore, the slope of the line is $\frac{1}{2}$ . Plug this into $y=mx+b$ :

$y=\frac{1}{2}x+b$

<u>2) Determine the y-intercept (b)</u>

$y=\frac{1}{2}x+b$

Plug in one of the given points and solve for b

$-5=\frac{1}{2}(2)+b\\-5=1+b$

Subtract 1 from both sides to isolate b

$-5-1=1+b-1\\-6=b$

Therefore, the y-intercept of the line is -6. Plug this back into $y=\frac{1}{2}x+b$ :

$y=\frac{1}{2}x+(-6)\\y=\frac{1}{2}x-6$

I hope this helps!

6 0

3 years ago

Find the derivative of f(x) = negative 11 divided by x at x = 9.

zavuch27 [327]

Remember the power rule
$\frac{dy}{dx} x^m=mx^{m-1}$
and the constant multipule rule
$\frac{dy}{dx} cf(x)=c \frac{dy}{dx} f(x)$ wher c is a constant

so

$f(x)= \frac{-11}{x}$ can be rewritten as
$f(x)=-11x^{-1}$
take deritivitve ad apply constnat multipule and power rule
$f'(x)=-11(-1x^{-2})$
$f'(x)=11(x^{-2})$
$f'(x)= \frac{11}{x^2}$

at x=9

$f'(9)= \frac{11}{9^2}$
$f'(9)= \frac{11}{81}$

4 0

2 years ago