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Marat540 [252]
2 years ago
9

Last time. (fifty each) F ree p oints! Jess is signing out, but want to make everyone's day. Have a great day!

Mathematics
2 answers:
Svetllana [295]2 years ago
6 0

Answer:

Umm.. thanks so much

Step-by-step explanation:

gulaghasi [49]2 years ago
6 0

Answer:

well then

Step-by-step explanation:

i shall take these points with gratitude.

i thank you with the power of god and anime

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What is the answer (x + 3)2 – 5 = 0
ElenaW [278]

x= -1/2 is the answer to your question. Mark as brainliest!!!!

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2 years ago
Consider the following dot plots.
motikmotik
The <u>correct answer</u> is:

A) The medians are both between 10 and 14 emails.

Explanation:

The <u>mode </u>is the easiest measure to find of a data set.
The <u>mode </u>of a data set is the data value that appears the most often.  In plot A, there are 3 dots at 10 and 3 dots at 15; this means the modes are 10 and 15.

In plot B, there are 3 dots at 5 and 3 dots at 15; this means the modes are 5 and 15.

They <u>do not have the same modes</u>.

The <u>median </u>of a data set is the middle value.  There are 10 dots in each dot plot; this means the medians will each be between two data points.

For plot A, we can see that the middle value is between 10 and 15.  
For plot B, we can see that the middle value is between 10 and 15.

This means that choice A is correct, the medians of both are between 10 and 14.
8 0
3 years ago
(2k+11)<br> 131°<br> What is the value of k
Triss [41]
The value of k is 60


131 - 11 = 120
120/2 = 60

hope this helped !
6 0
3 years ago
Read 2 more answers
Answer all the questions
Verizon [17]
20. x > 15
19. x \leq -8
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5 0
3 years ago
The area of a circular sun spot is growing at a rate of 1,200 km2/s.
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A)

\bf \textit{area of a circle}\\\\&#10;A=\pi r^2&#10;\\\\\\&#10;\cfrac{dA}{dt}=\pi \cdot 2r\cfrac{dr}{dt}\implies \cfrac{dA}{dt}=2\pi r\cfrac{dr}{dt}\implies \cfrac{\frac{dA}{dt}}{2\pi r}=\cfrac{dr}{dt}\\\\&#10;-----------------------------\\\\&#10;\left. \cfrac{dr}{dt}  \right|_{r=3000}\implies \cfrac{1200}{2\pi \cdot 3000}=\cfrac{dr}{dt}\\\\

B)

\bf A=\pi r^2\qquad A=490000\implies 490000=\pi r^2\implies \sqrt{\cfrac{490000}{\pi }}=r&#10;\\\\\\&#10;\left. \cfrac{dr}{dt}  \right|_{r=\sqrt{\frac{490000}{\pi }}}\implies \cfrac{1200}{2\pi \cdot \sqrt{\frac{490000}{\pi }}}=\cfrac{dr}{dt}&#10;
8 0
2 years ago
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