Let x be the length of the train.
On the basis of the observer;
Speed of the train = x/6
On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20
Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
Speed = x/6 = (350+x)/20 = 150/6 = 500/20 = 25 m/s.
Therefore,
Length of train = 150 m
Speed of train = 25 m/s
Answer:
7/16 = 0.4375
Step-by-step explanation:
sry
Answer:
A
Step-by-step explanation:
9 * 7 = 63
9 * 8 = 72
9 * 10 = 90
Answer:
3x^2+1.5x-9
Step-by-step explanation:
(f+g) (x)
=f(x)+g(x)
=x/2-3+3x^2+x-6
=3x^2+1.5x-9