Okay lets create an eqn from that information
A first int, B second int, C third int, D fourth int.
B = A + 2
C = A + 4
D = A + 6
A is the smallest integer
B + D = 0.5 (A + C)
Now lets substitute
(A + 2) + (A + 6) = 0.5(A + (A + 4))
now lets dist
2a + 8 = 0.5(2a +4)
2a + 8 = a + 2
a + 8 = 2
a = -6
B = -6 +2
B = -4
C = -6 + 4
C = -2
D = -6 + 6
D = 0
Now using B + D = 0.5(A + C)
-4 + 0 = 0.5(-6 + (-2))
-4 = 0.5 (-8)
-4 = -4
Correct
Therefore, First integer is -6, second integer is -4, third integer is -2 and fourth integer is 0
A - actuary...........that is the answer
Answer:
A number line with an open circle on -6, shading to the left, and a closed circle on 5, shading to the right
Step-by-step explanation:
we have
----> inequality A
or
----> inequality B
<em>Solve inequality A</em>
The solution of inequality A is the interval ----> (-∞, -6)
<em>Solve inequality B</em>
The solution of inequality B is the interval ----> [5,∞)
The solution of the compound inequality is
(-∞, -6) ∪ [5,∞)
The solution is
A number line with an open circle on -6, shading to the left, and a closed circle on 5, shading to the right
Let us assume the two unknown numbers to be "x" and "y".
Then
x + y = 37
And
xy = - 210
x = - 210/y
Now let us put the value of "x" in the first equation, we get
x + y = 37
- (210/y) + y = 37
y^2 - 210 = 37y
y^2 - 37y - 210 = 0
y^2 - 42y + 5y - 210 = 0
y(y - 42) + 5(y - 42) = 0
(y - 42)(y + 5) = 0
So when
y - 42 = 0
y = 42
Then
x = -(210/42)
= - 5
Again when
y + 5 = 0
y = -5
Then
x = 42
So the two unknown numbers are 42 and -5. I hope the procedure is clear enough for you to understand.
Answer:
It's 3
Step-by-step explanation: