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3 years ago

James is studying different kinds of weather.

Mathematics

1 answer:

expeople1 [14]3 years ago

7 0

What ?

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I need help on this problem please help me.

a_sh-v [17]

Answer:

150 mL

Step-by-step explanation:

Let x represent the quantity of 75% solution needed. The total amount of alcohol in the 60% mixture will be ...

75%·x + 10%·45 = 60%·(x+45) . . . . . there will be x+45 mL of solution in the end

0.15x = 22.5 . . . . . . . . . . . . . . . . . . . . simplify, subtract .60x+4.5

22.5/0.15 = x = 150 . . . . . . . . . . . . . . mL of 75% solution needed

You will need 150 mL of the 75% solution.

3 0

4 years ago

Geometry Homework Question

mash [69]

Answer:

Distance is 8.485

Midpoint is (3,4)

Step-by-step explanation:

Use the points (-1,7) and (5,1)

Insert them into the equation and solve for D

$D=\sqrt{x} ((5-(-1))^2 + (1-7)^2)\\D=\sqrt{x} ((6)^2 + (-6)^2)\\D=\sqrt{x} (36+36)\\D=\sqrt{x} (72)\\D=8.485$

Insert points into second equation to find midpoint

$(\frac{_1+5}{2} , \frac{7+1}{2}) \\(\frac{6}{2} ,\frac{8}{2} )\\(3,4)$

7 0

3 years ago

The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000

valina [46]

Answer: 61,750 miles

Step-by-step explanation:

Given : The p-value of the tires to outlast the warranty = 0.96

The probability that corresponds to 0.96 from a Normal distribution table is 1.75.

Mean : $\mu=60,000\text{ miles}$

Standard deviation : $\sigma=1000\text{ miles}$

The formula for z-score is given by : -

$z=\dfrac{x-\mu}{\sigma}\\\\\Rightarrow\ 1.75=\dfrac{x-60000}{1000}\\\\\Rightarrow\ x-60000=1750\\\\\Rightarrow\ x=61750$

Hence, the tread life of tire should be 61,750 miles if they want 96% of the tires to outlast the warranty.

3 0

3 years ago

Question 16 (Essay Worth 7 points)<br><br> Verify the identity.<br><br> tan (x + π/2) = -cot x

Rus_ich [418]

Step-by-step explanation:

We know that tan=sin/cos, so tan(x+π/2)=

$\frac{sin(x+pi/2)}{cos(x+pi/2)}$

Then, we know that sin(u+v)=sin(u)cos(v)+cos(u)sin(v),

so our equation is then

$\frac{sin(x)cos(\pi/2)+cos(x)sin(\pi/2)}{cos(x+\pi/2)} = \frac{cos(x)}{cos(x+\pi/2) }$

Then, cos(u+v)=cos(u)cos(v)-sin(u)sin(v), so our expression is then

$\frac{cos(x)}{cos(x)cos(\pi/2)-sin(x)sin(\pi/2)} = \frac{cos(x)}{-sin(x)} = -cot(x)$

6 0

3 years ago

A number is chosen at random from 1 to 25. Find the probability of selecting an odd number or multiples of 5. *

Ymorist [56]

Answer:

Odd number: 13/25 (52%)

Multiples of 5: 5/25 (20%)

Step-by-step explanation:

There are 13 odd numbers between 1 and 25 so you have a 13/25 chance which is 52% (13/25 = 0.52). There are 5 multiples of 2 between 1 and 25 so you have a 5/25 chance which is 20% (5/25 = 0.2).

8 0

3 years ago