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galben [10]
1 year ago
11

How does the luminosity of this star compare with that of the other three (hip 87937, hip 108870, and tau cet)?

Computers and Technology
1 answer:
Afina-wow [57]1 year ago
6 0

Answer:

Regulus is the most luminous. Regulus is the least luminous

Explanation:

  • Transcribed image text: Of the three stars you've observed (HIP 87937, HIP 108870, and Tau Cet), which one is more luminous?
  • View Available Hint(s) Tau Cet O HIP 87937 O HIP 108870
  • They have the same luminosity.

To learn more about it, refer

to https://brainly.in/question/413163

#SPJ4

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5.14 Describe how the compare and swap() instruction can be used to provide mutual exclusion that satisfies the bounded-waiting
Naddik [55]

Answer:

Explained below

Explanation:

Compare and Swap(C&S) is simply an atomic operation whereby the compare and swap operations are automatically executed.

Now compare and Swap basically needs 3 arguments namely:

- 2 old values which we will label X and Y

- 1 new value which is written in X that we will call Z

Thus, we now have; C & S = {X, Y, Z}

To explain this well, let X be a variable where X has a value of 7.

Now, if a programmer gives a program me that X be multiplied by 2,then what C&S operation will do is;

I) Y = X where Y is a new variable.

II) Result = C&S(X, Y, X*7)

Variable X is global and this means that mere than one process and more than 1 thread can see the variable X.

Now, if a process named P1 wants multiply the variable X by 7 using C&S operation, it will first make a local copy of variable X (which in this case is now the new variable Y). After that it will atomically compare X & Y and if they are equal, it will replace X with 10X.

However, if they are not equal, P1 will re-read value of X into Y and carry of C&S instruction again.

8 0
2 years ago
Write an application that prompts a user for a month, day, and year. Display a message that specifies whether the entered date i
gizmo_the_mogwai [7]

Answer:

Following is given the code with all necessary description given as comments in it. I hope it will help you!

Explanation:

4 0
3 years ago
Write a function addUpSquaresAndCubes that adds up the squares and adds up the cubes of integers from 1 to N, where N is entered
avanturin [10]

Answer:

All functions were written in python

addUpSquaresAndCubes Function

def addUpSquaresAndCubes(N):

    squares = 0

    cubes = 0

    for i in range(1, N+1):

         squares = squares + i**2

         cubes = cubes + i**3

    return(squares, cubes)

sumOfSquares Function

def sumOfSquares(N):

    squares = 0

    for i in range(1, N+1):

         squares = squares + i**2

    return squares

sumOfCubes Function

def sumOfCubes(N):

    cubes = 0

    for i in range(1, N+1):

         cubes = cubes + i**3

    return cubes

Explanation:

Explaining the addUpSquaresAndCubes Function

This line defines the function

def addUpSquaresAndCubes(N):

The next two lines initializes squares and cubes to 0

    squares = 0

    cubes = 0

The following iteration adds up the squares and cubes from 1 to user input

    for i in range(1, N+1):

         squares = squares + i**2

         cubes = cubes + i**3

This line returns the calculated squares and cubes

    return(squares, cubes)

<em>The functions sumOfSquares and sumOfCubes are extract of the addUpSquaresAndCubes.</em>

<em>Hence, the same explanation (above) applies to both functions</em>

7 0
3 years ago
Which is the right answer
Maksim231197 [3]

Answer:

B

Explanation:

I think.

5 0
2 years ago
Read 2 more answers
Which unique address is a 128-bit address written in hexadecimal?
pentagon [3]
Every hexadecimal digit represents 4 bits, so the address has 128/4 = 32 digits.

A GUID (Globally Unique IDentifier) has 128 bits. They are usually written like this:

{38a52be4-9352-4<span>53e-af97-5c3b448652f0}.</span>

There are different types of guids, depending on how they are generated. The first digit of the third group reveals the type. In the example above it is 4. A type 4 guid is fully random (except of course for the 4).

3 0
2 years ago
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