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3 years ago

URGENT PLEASE HELP ME what side is the adjacent and opposite

Mathematics

1 answer:

trapecia [35]3 years ago

5 0

Answer: Line DE is the adjacent while line EF is the opposite.

Step-by-step explanation: This is a right angled triangle and the reference angle has been marked at point D. If you drew a line from that angle it would touch the triangle at line line EF. It’s facing the reference angle and that’s why it’s called the “opposite.”

The line that lies between the reference angle and the right angle is called the adjacent and that’s line DE in this triangle. The hypotenuse has already been identified for you, and that’s the line that’s opposite the right angle (it’s always the longest side).

**Please note that the opposite and adjacent ALWAYS depends on where the reference angle is positioned.

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Find and x and y PLEASE HELP

Bogdan [553]

Answer:

Step-by-step explanation:

x is 79 and y is 47

6 0

3 years ago

Which is the rationalized form of the expression sqrtx/sqrtx+sqrt7

ArbitrLikvidat [17]

Answer:

(x - √7*√x) / (x - 7)

Step-by-step explanation:

I suppose your expression is √x / (√x + √7)

(√x * (√x - √7)) / ((√x + √7) * √x - √7)) = (√x * √x - √7 * √x) / (x - 7)

= (x - √7*√x) / (x - 7)

5 0

3 years ago

Solve each equation. I don't know this

MArishka [77]

1. $(2x - 3)(x + 7) = 0$
 $2x^{2} + 14x - 3x - 21 = 0$
 $2x^{2} + 11x - 21 = 0$

 $x = \frac{-11 +/- \sqrt{11^{2} - 4(2)(-21)}}{2(2)}$

 $x = \frac{-11 +/- \sqrt{121 + 168}}{4}$

 $x = \frac{-11 +/- \sqrt{289}}{4}$

 $x = \frac{-11 +/- 17}{4}$

 $x = -2.75 +/- 4.25$
 $x = -2.75 + 4.25$ $x = -2.75 - 4.25$
 $x = 1.5$ $x = -7$
---------------------------------------------------------------------------------------------------------- 2. $8x(2x - 5) = 0$
 $8x(2x) - 8x(5) = 0$
 $16x^{2} - 40x = 0$
 $16x^{2} - 4x + 0 = 0$

 $x = \frac{-(-40) +/- \sqrt{(-40)^{2} - 4(16)(0)}}{2(16)}$

 $x = \frac{40 +/- \sqrt{1600 - 0}}{32}$

 $x = \frac{40 +/- \sqrt{1600}}{32}$

 $x = \frac{40 +/- 40}{32}$

 $x = 1.25 +/- 1.25$
 $x = 1.25 + 1.25$ $x = 1.25 - 1.25$
 $x = 2.5$ $x = 0$
----------------------------------------------------------------------------------------------------------
3. $x^{2} + 3x - 10 = 0$

 $x = \frac{-3 +/- \sqrt{3^{2} - 4(1)(-10)}}{2(1)}$

 $x = \frac{-3 +/- \sqrt{9 + 40}}{2}$

 $x = \frac{-3 +/- \sqrt{49}}{2}$

 $x = \frac{-3 +/- {7}}{2}$

 $x = -1.5 +/- 3.5$
 $x = -1.5 + 3.5$ $x = -1.5 - 3.5$
 $x = 2$ $x = -5$
----------------------------------------------------------------------------------------------------------
4. $x^{2} = 13x - 36$
 $x^{2} - 13x + 36 = 13x - 13x - 36 + 36$
 $x^{2} - 13x + 36 = 0$

 $x = \frac{-(-13) +/- \sqrt{(-13)^{2} - 4(1)(36)}}{2(1)}$


 $x = \frac{13 +/- \sqrt{169 - 144}}{2}$

 $x = \frac{13 +/- \sqrt{25}}{2}$

 $x = \frac{13 +/- 5}{2}$

 $x = 6.5 +/- 2.5$
 $x = 6.5 + 2.5$ $x = 6.5 - 2.5$
 $x = 9$ $x = 4$
----------------------------------------------------------------------------------------------------------
5. $3x^{2} - 7x + 2 = 0$

 $x = \frac{-(-7) +/- \sqrt{(-7)^{2} - 4(1)(2)}}{2(3)}$

 $x = \frac{7 +/- \sqrt{49 - 8}}{6}$

 $x = \frac{7 +/- \sqrt{41}}{6}$

 $x = \frac{7 +/- 6.403124237432849}{6}$

 $x = 1.167+/- 1.06718737290547$
 $x = 1.67 + 1.06718737290547$ $x = 1.167 - 1.06718737290547$
 $x = 2.73718737290547$ $x = 0.60281262709453$
----------------------------------------------------------------------------------------------------------
6. $10x^{2} - 10x + 9 = 5x^{2} + 4x + 1$
 $10x^{2} - 5x^{2} - 10x + 10x + 9 - 1 = 5x^{2} - 5x^{2} + 4x + 10x + 1 - 1$
 $5x^{2} + 8 = 14x$
 $5x^{2} - 14x + 8 = 14x - 14x$
 $5x^{2} - 14x + 8 = 0$

 $x = \frac{-(-14) + \sqrt{(-14)^{2} - 4(5)(8)}}{2(5)}$

 $x = \frac{14 +/- \sqrt{196 - 160}}{10}$

 $x = \frac{14 +/- \sqrt{36}}{10}$ .

 $x = \frac{14 +/- 6}{10}$

 $x = 1.4 +/- 0.6$
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 $x = 2$ $x = 0.8$

5 0

4 years ago

Jolie sends between 22 and 23 text messages per day. Each text message costs $0.89. Suppose Jolie's cellular bill spans a period

kondor19780726 [428]

Answer:

C. $945

Step-by-step explanation:

Cost of 1 cellular bill = (number of text msgs per day) x (cost per text msg) x (number of days in billing period)

in this case, it is given that :

cost per text msg = $0.89

number of texts per day = 22 or 23

billing cycle = 6 weeks = 6 x 7 = 42 days

hence,

Cost of 1 cellular bill = (22 or 23) x $0.89 x 42 days

if she sends 22 messages,

Cost of 1 cellular bill = (22) x $0.89 x 42 days= $822.36

if she sends 23 messages,

Cost of 1 cellular bill = (2) x $0.89 x 42 days= $859.74

if we compare thse 2 numbers that we have calculated with the choices, the closest match would be C. $945. The rest are just too far away in comparison.

8 0

4 years ago

PLEASE HELP (100 POINTS)

Artyom0805 [142]

$\\ \rm\Rrightarrow f(x)=-5cos\dfrac{x}{2}+5$