The formula of a distance between two points:

We have the points P(2, 2) ans Q(7, 4). Substitute:

<h3>Answer: PQ = 5.4</h3>
Answer:
12 1/3
Step-by-step exp
First, you need to add up 11/4 and
6 1/2
11/ 4 + 6 1/2 = 11/4 + 13/2 = 37 / 4
To find how many 3/4 we have in 37/4, we simply dividw 37/4 by 3/4
37/4 ÷ 3/4
= 37/4 × 4/3 (4 will cancel out 4)
= 37/3
=12 1/3
Answer:
We cannot say that the mean wake time are different before and after the treatment, with 98% certainty. So the zopiclone doesn't appear to be effective.
Step-by-step explanation:
The goal of this analysis is to determine if the mean wake time before the treatment is statistically significant. The question informed us the mean wake time before and after the treatment, the number of subjects and the standard deviation of the sample after treatment. So using the formula, we can calculate the confidence interval as following:
![IC[\mu ; 98\%] = \overline{y} \pm t_{0.99,n-1}\sqrt{\frac{Var(y)}{n}}](https://tex.z-dn.net/?f=IC%5B%5Cmu%20%3B%2098%5C%25%5D%20%3D%20%5Coverline%7By%7D%20%5Cpm%20t_%7B0.99%2Cn-1%7D%5Csqrt%7B%5Cfrac%7BVar%28y%29%7D%7Bn%7D%7D)
Knowing that
:
![IC[\mu ; 98\%] = 98.9 \pm 2.602\frac{42.3}{4} \Rightarrow 98.9 \pm 27.516](https://tex.z-dn.net/?f=IC%5B%5Cmu%20%3B%2098%5C%25%5D%20%3D%2098.9%20%5Cpm%202.602%5Cfrac%7B42.3%7D%7B4%7D%20%5CRightarrow%2098.9%20%5Cpm%2027.516)
![IC[\mu ; 98\%] = [71.387 ; 126,416]](https://tex.z-dn.net/?f=IC%5B%5Cmu%20%3B%2098%5C%25%5D%20%3D%20%5B71.387%20%3B%20126%2C416%5D)
Note that
so we cannot say, with 98% confidence, that the mean wake time before treatment is different than the mean wake time after treatment. So the zopiclone doesn't appear to be effective.
38 , because since its 90 degrees at exact, your subtract 90 from 52 and you would get 38 for your x value
Answer:
11 students
Step-by-step explanation:
We can see that there are 6 students with 3 siblings, 4 students with 4 siblings, and 1 student with 6 siblings.
Adding all of these together will tell us how many students have 3 or more siblings.
6 + 4 + 1 = 11
So, there are 11 students with 3 or more siblings.