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Marina86 [1]
3 years ago
7

Finding the difference between 827 and 513

Mathematics
2 answers:
koban [17]3 years ago
4 0
Answer: 314

Take each number place and subtract them from each other.
Shtirlitz [24]3 years ago
3 0

Answer:

314

Step-by-step explanation:

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The sporting goods store is offering an 18% discount on a trampoline. The advertised price before the discount is $399. How much
bezimeni [28]

Answer:

327.18

Step-by-step explanation:

399-18%=327.18

5 0
3 years ago
Question 5
Natali5045456 [20]

Answer:

D) no solution

Step-by-step explanation:

2x - 4y = 14

X + 2y = 7

2x - 4y + x + 2y = 14 + 7

2x - 4y + x + 2y = 21

3x - 2y = 21

no solution

8 0
3 years ago
Read 2 more answers
A website manager has noticed that during the evening​ hours, about 3.23.2 people per minute check out from their shopping cart
aleksandrvk [35]

Answer:

1.  c. Poisson

2. 0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. 0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

Step-by-step explanation:

We have only the mean, which means that the Poisson distribution is used to solve this question, and thus the answer to question 1 is given by option c.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 3.2 minutes:

This means that \mu = 3.2n, in which n is the number of minutes.

2. What is the probability that in any one minute at least one purchase is​ made?

n = 1, so \mu = 3.2.

This probability is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3.2}*3.2^{0}}{(0)!} = 0.0408

So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0408 = 0.9592

0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. What is the probability that no one makes a purchase in the next 2​ minutes?

2 minutes, so n = 2, \mu = 3.2(2) = 6.4

This probability is P(X = 0). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-6.4}*6.4^{0}}{(0)!} = 0.0017

0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

7 0
3 years ago
8/9÷3= 7/8 1/5 8/27 2/3​
natima [27]
8/9 divided by 3 = 8/27

have a wonderful day! the steps are down below! :)

4 0
3 years ago
Solve h + 6 / 5 = 2 <br> Solve for h
skelet666 [1.2K]

Answer:

-1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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