All categories

3 years ago

Finding the difference between 827 and 513

Mathematics

2 answers:

koban [17]3 years ago

4 0

Answer: 314

Take each number place and subtract them from each other.

Shtirlitz [24]3 years ago

3 0

Answer:

314

Step-by-step explanation:

You might be interested in

I need help with a/d

sveta [45]

What’s the question asking??

3 0

2 years ago

Read 2 more answers

5. While bird watching, Gabrielle saw 6 robins and 3 blue jays.

Semenov [28]

Answer:

Neither. They both saw the same amount of birds.

Step-by-step explanation:

Gabrielle saw 9 birds, but so did Chase. 6+3 is 9. 3+6 is also 9. The commutative property of addition states that a+b=b+a.

4 0

3 years ago

Referring to the figure find m∠3

kkurt [141]

Answer:

Measure of angle 3 = 30⁰

Because vertically opposite angles are always equal

5 0

3 years ago

MAX POINTS!!! Write and solve a system of equations. Be sure to label the variables. The difference of two numbers is two. Two t

Cerrena [4.2K]

Answer:

5 and 3

Step-by-step explanation:

Let the numbers be x and y.

The equations are:

x - y = 2
2x + y = 13

Add up the equations to eliminate y and solve for x:

x - y + 2x + y = 2 + 13
3x = 15
x = 15/3
x = 5

Now find the value of y:

y = x - 2
y = 5 - 2
y = 3

3 0

2 years ago

Read 2 more answers

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

3 years ago