All categories

2 years ago

Solve the equation x-20.7=9.5 for x

Mathematics

2 answers:

kenny6666 [7]2 years ago

8 0

The answer will come out to 30.2

Murrr4er [49]2 years ago

3 0

X= 30.2, solve by isolating x.
x= 20.7 + 9.5

You might be interested in

What is the range of a cosine function?

salantis [7]

Answer:

The sine and cosine functions have a period of 2π radians and the tangent function has a period of π radians. Domain and range: From the graphs above we see that for both the sine and cosine functions the domain is all real numbers and the range is all reals from −1 to +1 inclusive.

Step-by-step explanation:

6 0

3 years ago

Find the length of a line segment CD with endpoint C at (-3,1) and endpoint D at (5,6)

lutik1710 [3]

I believe your length would be 8, because -3 to get to 0 is 3 then after that you still have 5 so you add them and get 8

8 0

2 years ago

Two parallel lines are cut by a transversal such that two alternate interior angles are formed. If one of the angles is 72 degre

levacccp [35]

Answer:

x=18

Step-by-step explanation:

5x+2=72

-2 -2

5x=70

---------

x=18

3 0

2 years ago

I need answer for #11

balandron [24]

Answer: The first step would be to multiply the first equation by 3 and the second by 2 so you can eliminate x.

7 0

2 years ago

Read 2 more answers

Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to

ra1l [238]

Answer:

The confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

The sample size is n = 41

For a 95% confidence the level of significance is $\alpha = [100 - 95]\% = 0.05$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }= 1.96$

For a 90% confidence the level of significance is $\alpha = [100 - 90]\% = 0.10$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }= 1.645$

So we see with decreasing confidence level the critical value decrease

Now the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{n} }$

given that other values are constant and only $Z_{\frac{\alpha }{2} }$ is varying we have that

$E\ \ \alpha \ \ Z_{\frac{\alpha }{2} }$

Hence for reducing confidence level the margin of error will be reducing

The confidence interval is mathematically represented as

$\= x - E < \mu < \= x + E$

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value reduces, the margin of error reduces and the confidence interval becomes narrower

3 0

2 years ago

Solve the equation x-20.7=9.5 for x￼

Solve the equation x-20.7=9.5 for x