2 years ago

Solve the equation x-20.7=9.5 for x

Mathematics

2 answers:

kenny6666 [7]2 years ago

8 0

The answer will come out to 30.2

Murrr4er [49]2 years ago

3 0

X= 30.2, solve by isolating x.
x= 20.7 + 9.5

You might be interested in

The total arm and blade of a windshield wiper is 12 in. long and rotates back and forth through an angle of 85°. The shaded regi

valkas [14]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Help please need asap!! Thank you

olganol [36]

Answer:

your welcome

Step-by-step explanation:

....bbc

6 0

2 years ago

Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

6 0

3 years ago

Plz help!!! ASAP! GIVE BRAINLIEST AND GIVING POINTS!!!!!

Studentka2010 [4]

Answer:

-8

Step-by-step explanation:

-8m⁴ n⁴

m = 0.5 = 1/2

n = 2

Substitute

-8 * (1/2)⁴ * (2)⁴

-8 * (1/16) * (16)

-8

4 0

2 years ago

The parabola y=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class

oksano4ka [1.4K]

Y=(x-h)^2+k where (h,k) is the vertex

So, equation of new parabola is:

y=(x+1)^2+7

7 0

3 years ago

Solve the equation x-20.7=9.5 for x￼

Solve the equation x-20.7=9.5 for x