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7nadin3 [17]
4 years ago
8

Round 71,290 to the nearest ten

Mathematics
1 answer:
igor_vitrenko [27]4 years ago
4 0
71,290 because the 0 can't make 90 go up.
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Six times the sum of three consecutive odd integers is 18.Find the integers 1st integers (smallest of 3): 2nd integers (middle o
OLga [1]

Answer:

-1, 1 and 3.

Step-by-step explanation:

Let the integers be n, n + 2 and n + 4, then

6( n + n+2 + n + 4) = 18

6(3n + 6) = 18    Divide through by 6:

3n + 6 = 3

3n = -3

n = -1

So the integers are -1, 1 and 3.

5 0
3 years ago
NEED HELP PLEASE BEEN WORKING 1 HOUR
Ratling [72]

an=9432+9432*0.075(n-1)

n>1

second problem

9432+9432*0.075(n-1)

plug in 15

9432+9432*0.075(15-1)

multiplication

9432+9903.6

add

19335.6

8 0
3 years ago
. In April, it rained 1/4 of an inch on 15 different days. How many inches of rain fell
notka56 [123]

Answer:

3.75, or \frac{15}{4} inches of rain during the 15 days of April.

Step-by-step explanation:

All you have to do is add \frac{1}{4} 15 times to get that number.

\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} +\frac{1}{4} = 3.75

You can also do 15 times \frac{1}{4}, which will result in the same thing.

#teamtrees #WAP (Water And Plant)

5 0
3 years ago
Please help me with this, I need help here, it is missing. Already. Please. ​
Sedbober [7]

Answer:

4y 3x

Step-by-step explanation:

3 0
3 years ago
. Shanice is making a garden. The area of the garden is 24 ft2. Use the following shape and information to find the base (6−4) a
crimeas [40]

Answer:

The base and height  of the garden are 4.60 ft and 5.60 ft.

Step-by-step explanation:

The area of the garden is, <em>A</em> = 24 ft².

The base height of the garden are:

base (<em>b</em>) = 6x - 4

height (<em>h</em>) = x + 3

Compute the value of <em>x</em> as follows:

A=\frac{1}{2}\times b \times h\\\\24=\frac{1}{2}\times (6x-4) \times (x+3)\\\\48=6x^{2}+18x-4x-12\\\\6x^{2}+14x-60=0\\\\3x^{2}+7x-30=0\\

The last equation is a quadratic equation.

Compute the roots of the quadratic equation as follows:

x = \frac{ -b \pm \sqrt{b^2 - 4ac}}{ 2a }\\x = \frac{ -14 \pm \sqrt{14^2 - 4(3)(-30)}}{ 2(3) }\\x = \frac{ -14 \pm \sqrt{556}}{ 6 }\\x = \frac{ -14 }{ 6 } \pm \frac{2\sqrt{139}\, }{ 6 }\\x = -\frac{ 7}{  3 } \pm \frac{ \sqrt{139}\, }{  3 }\\x = 1.59661\\x\approx 1.60

The value of base and height are:

\text{base}=6x-4=(6\times 1.60)-4=5.60\ \text{ft}\\\\\text{height}=x+3=1.60+3=4.60\ \text{ft}

Thus, the base and height  of the garden are 4.60 ft and 5.60 ft.

3 0
3 years ago
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