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4 years ago

16/ = -8 _/12 = -6

Mathematics

2 answers:

telo118 [61]4 years ago

7 0

Answer:

Step-by-step explanation:

16/x = -8

-8x = 16

x = -2

x/12 = -6

x = -72

Karolina [17]4 years ago

6 0

Answer:

1.) - 2

2.) - 72

Step-by-step explanation:

hope this helps

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Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:

ryzh [129]

First find the critical points of f :

$f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7$

$\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1$

$\dfrac{\partial f}{\partial y}=6y=0\implies y=0$

so the point (1, 0) is the only critical point, at which we have

$f(1,0)=-7$

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

$f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t$

Find the critical points of g :

$\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0$

$\implies\sin t=0\text{ OR }1+5\cos t=0$

$\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi$

where n is any integer. We get 4 critical points in the interval [0, 2π) at

$t=0\implies f(10,0)=155$

$t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299$

$t=\pi\implies f(-10,0)=235$

$t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299$

So f has a minimum of -7 and a maximum of 299.

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3 years ago

I need help with this

AfilCa [17]

Answer:

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Step-by-step explanation:

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3 years ago

What is the value of r of the geometric series?

Leni [432]

Answer:

A) 0.8

Step-by-step explanation:

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3 years ago

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The number of chocolates sold can be determined by the equation: P=$.63c, where P is the price and c is the number of chocolates

balu736 [363]

Answer:

p = price

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c = number of pieces of chocolate

just multilply the number of pieces of chocolate by 0.63 to get the total price

Step-by-step explanation:

5 0

4 years ago

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Which is equivalent to the complex number i^32?

Ksivusya [100]

Answer:

where i^2 = -1 (minus one)

So, i^2 = -1

i^4 = (i^2)^2 = (-1)^2 = -1 X-1 = 1

like ;

i^32 = (i^2)^16 = (-1)^16 = -1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X

= 1

Step-by-step explanation:

4 0

4 years ago

16/__ = -8 ___/12 = -6

16/ = -8 _/12 = -6