Exponential Function.
Plotting the graph using this table gives the first figure. An exponential function has this kind of graph.
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature =
= 15°c
The final temperature =
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × (
-
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer: 81%
Step-by-step explanation:
Answer:
x = 43 1/3 degrees
Step-by-step explanation:
sum of interior angles in a triangle = 180 degrees
30 + (3x - 9) + 29 = 180
30 + 29 + (3x - 9) = 180
59 + (3x - 9) = 180
(3x - 9) = 180 - 59
(3x - 9) = 121
3x = 121 + 9
3x = 130
x = 43 1/3
Answe the awnser is b
Step-by-step explanation: