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cestrela7 [59]
2 years ago
14

Find the side lengths of each triangle ​

Mathematics
1 answer:
Levart [38]2 years ago
7 0

Answer:

Step-by-step explanation:

So add the numbers on each side together

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4x + 5y = 10
Vika [28.1K]

Answer:

For A = 32/5 and B = 8 the system of equations will have infinitely many solutions.

Step-by-step explanation:

Given equations are:

4x + 5y = 10

Ax + By = 16

The general form of linear equation in two variables is given by:

ax+by = c

Here a, b and c are constants and x,y are variables.

In the given equations, after comparing with the general form

a_1 = 4\\b_1 = 5 \\c_1 = 10\\a_2 = A\\b_2 =B\\c_2 = 16

"In order for a system of equations to have infinity many solutions,

\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} "

Putting the values we get

\frac{4}{A} = \frac{5}{B} = \frac{10}{16}\\\frac{4}{A} = \frac{5}{B} = \frac{5}{8}\\Now\\\frac{4}{A} = \frac{5}{8}\\\frac{A}{4} = \frac{8}{5}\\A = \frac{8}{5} * 4\\A = \frac{32}{5}\\And\\\frac{5}{B} = \frac{5}{8}\\\frac{B}{5} = \frac{8}{5}\\B = 8

Hence,

For A = 32/5 and B = 8 the system of equations will have infinitely many solutions.

5 0
2 years ago
Which of the following is the best estimate of the direction of the given vector?
notka56 [123]

Answer:

The direction of the given vector is 45° N of W

Step-by-step explanation:

* Lets revise the four directions with the four quadrants

- The four directions are:

# North which represented by the positive part of y-axis

# South which represented by the negative part of y-axis

# East which represented by the positive part of x-axis

# West which represented by the negative part of y-axis

∴ The first quadrant is between the East and the North

∴ The second quadrant is between the West and the North

∴ The third quadrant is between the West and the South

∴ The fourth quadrant is between the East and the South

* The direction of any vector is tan Ф, where Ф is the angle between

 the vector and the x-axis, then:

- The direction of North of East is 45° ⇒ first quadrant

- The direction of North of West is 45° ⇒ second quadrant

- The direction of South of West is 45° ⇒ third quadrant

- The direction of South of East is 45° ⇒ fourth quadrant

* Now lets solve the problem

∵ The direction of the vector is between the North and the West

  (its vertex in the second quadrant)

∴ Its direction is 45° North of West

* The direction of the given vector is 45° N of W

7 0
2 years ago
Kathryn bought five CDs. A week later half of all her CDs were lost during a move. There are now only 16 CDs left. With how many
yan [13]
She started off with 11
5 0
3 years ago
Does anyone know the answer
arsen [322]

Answer:

i cant see the photos

Step-by-step explanation:

sorry talaga

6 0
2 years ago
Read 2 more answers
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
2 years ago
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