Answer:
(a) the new angle the ladder makes with the ground is 
(b) the ladder slipped back about 5 meters
Step-by-step explanation:
Notice that the ladder doesn't change its length in the process.
So let's start from the initial situation , finding the distance from the ground at which the ladder touches the wall when the angle with the ground is 70^o. Notice that this situation is represented by a right angle triangle with the right angle between the wall and the ground (see attached image), and that we can use the sine function to find the side opposite to the 70 degree angle:

therefore 9.4 meters is approximately the height at which the ladder touches the wall initially.
Now, if the tip of the ladder goes down the wall 4 meters, it is now at 9.4 m - 4 m = 5.4 m from the ground. We can therefore use again the sine function to solve for the new angle:

To answer the second question we need to find the original distance from the wall that the bottom of the ladder was originally, and for that we can use the cosine function:

Now fro the new position of the bottom of the ladder relative to the wall:

then the difference in between those two distances is what we need:
8.4 m - 3.4 m = 5 m
Answer:inequality form x ≤ -1
for 3x + 9 ≤ 6
Step-by-step explanation:isolate the variable by dividing eash side by factors that dont contain the variable
Answer:
4.5 or 1 1/8
Step-by-step explanation:
2 1/4 is a full box to back 1/2 of the flour you need to divide 2 1/4 in half
Half of 2 is 1 & half of 1/4 is 1/8
to find the hypotenuse length you need to use the pythegorian therum and that will give you 29cm
The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417