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Leya [2.2K]
2 years ago
5

23 POINTS A 3-column table with 5 rows. Column 1 has entries Mean, median, mode, range, M A D. Column 2 is labeled Noah with ent

ries 87, 85.5, 85, 8, 2.67. Column 3 is labeled Gabriel with entries 87.17, 85, 86, 12, 3.22. What inferences can you make analyzing the data summary table? Check all that apply. Gabriel has a slightly higher quiz average than Noah. Noah is a better test taker than Gabriel. Noah has more variation in his quiz scores. Gabriel has more variation in his quiz scores. Gabriel’s quiz scores are more spread out than Noah’s quiz scores.
Mathematics
2 answers:
jek_recluse [69]2 years ago
6 0

Answer:

Answer:Noah and Gabriel are in the same English class. They have taken 6 quizzes so far. ... Gabriel's scores: 82, 85, 86, 86, 90, 94 Total of 523 ... What are Gabriel's mean, median, and mode? ... 1.1/5. 2. ryan28772020. ryan28772020. jd3sp4o0y. +16. jd3sp4o0y and 16 ... D. The mean is 83 and the median is 90.

Step-by-step explanation:

Nutka1998 [239]2 years ago
6 0

Answer:

1-Gabriel has a slightly higher quiz average than Noah., 4-Gabriel has more variation in his quiz scores., 5-Gabriel’s quiz scores are more spread out than Noah’s quiz scores.

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All you have to do is to the distributive method.

Step-by-step explanation:

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A rectangular field with one side along a river is to be fenced. Suppose that no fence is needed along the river, the fence on t
Andreas93 [3]

Answer:

a) Side Parallel to the river: 200 ft

b) Each of the other sides: 400 ft

Step-by-step explanation:

Let L represent side parallel to the river and W represent width of fence.

The required fencing (F) would be F=L+2W.

We have been given that field must contain 80,000 square feet. This means area of field must be equal to 80,000.

LW=80,000...(1)

We are told that the fence on the side opposite the river costs $20 per foot, and the fence on the other sides costs $5 per foot, so total cost (C) of fencing would be C=20L+5(2W)\Rightarrow 20L+10W.

From equation (1), we will get:

L=\frac{80,000}{W}

Upon substituting this value in cost equation, we will get:

C=20(\frac{80,000}{W})+10W

C=\frac{1600,000}{W}+10W

C=1600,000W^{-1}+10W

To minimize the cost, we need to find critical points of the the derivative of cost function as:

C'=-1600,000W^{-2}+10

-1600,000W^{-2}+10=0

-1600,000W^{-2}=-10

-\frac{1600,000}{W^2}=-10

-10W^2=-1,600,000

W^2=160,000

\sqrt{W^2}=\pm\sqrt{160,000}  

W=\pm 400

Since width cannot be negative, therefore, the width of the fencing would be 400 feet.

Now, we will find the 2nd derivative as:

C''=-2(-1600,000)W^{-3}

C''=3200,000W^{-3}

C''=\frac{3200,000}{W^3}

Now, we will substitute W=400 in 2nd derivative as:

C''(400)=\frac{3200,000}{400^3}=\frac{3200,000}{64000000}=0.05

Since 2nd derivative is positive at W=400, therefore, width of 400 ft of the fencing will minimize the cost.

Upon substituting W=400 in L=\frac{80,000}{W}, we will get:

L=\frac{80,000}{400}\\\\L=200

Therefore, the side parallel to the river will be 200 feet.

4 0
3 years ago
RYAN COMPLETED 1/8 of his test in 2/5 hour.if ryan's rate stayed the same,how much of his test was finished in one hour? help pl
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Answer:

<h2>5/16</h2>

Step-by-step explanation:

Multiply 1/8 by 2.5

1/8 x 2.5 = 5/16

Ryan will have completed 5/16 of his test at the 1 hour mark.

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