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3 years ago

I need help please!!!!!!!

Mathematics

1 answer:

k0ka [10]3 years ago

5 0

Answer:

1 roll of ribbon, 1 package of buttons, and 3 packages of beads

Step-by-step explanation:

Use the information you found about how much each makes to answer the question.

Lynette will make 6 decorations.

Since 1 roll makes 6, she needs 1 roll.

Since 1 package of buttons makes 6, she needs 1 package.

Since 1 package of beads makes 2, she needs 3 packages.

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∠1 and ∠2 are vertical angles. ∠2 has a measure of 93°. What is the measure of ∠1 ? Enter your answer in the box. °

kirza4 [7]

The measure of ∠1 is also <span>93° because vertically opposite angles are equal.</span>

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3 years ago

Read 2 more answers

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andreyandreev [35.5K]

Figure A which has two rays connected at a vertex is an angle in this scenario.

<h3>What is an Angle?</h3>

This is formed when two rays share a common endpoint with there being different types of angles.

The common endpoint shared forms a vertex which is why Figure A was chosen as the most appropriate choice.

Read more about Angle here brainly.com/question/25770607

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1 year ago

In a certain animal species, the probability that a female will have 0, 1, 2, 3, or 4 offspring in a given year is 0.31, 0.21, 0

blsea [12.9K]

Answer:

Step-by-step explanation:

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2 years ago

Help me with this to and use pemdas or not

PtichkaEL [24]

(72÷2)³ - 7 · 9 ÷ 9

First, parenthesis

72÷2 is 36

Next, exponents.

36³ is 46656.

Then, multiplication.

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After that, division.

63 ÷ 9 is 7

Finally, subtraction.

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3 years ago

7-18 use part 1 of the fundamental theorem of calculus to find the derivative of the function.

blondinia [14]

$\displaystyle h(x)=\int\limits_{1}^{\sqrt{x}}~\cfrac{z^2}{z^4+1}dz~\hspace{10em}\cfrac{dh}{du}\cdot \stackrel{chain~rule}{\cfrac{du}{dx}\implies \cfrac{dh}{dx}} \\\\[-0.35em] ~\dotfill\\\\ u=\sqrt{x}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}} \\\\[-0.35em] ~\dotfill$

$\cfrac{dh}{dx}\implies \displaystyle \cfrac{d}{du}\left[ \int\limits_{1}^{u}~\cfrac{z^2}{z^4+1}dz \right]\cdot \cfrac{1}{2\sqrt{x}}\implies \left[ \cfrac{u^2}{u^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}} \\\\\\ \stackrel{substituting~back}{\left[ \cfrac{(\sqrt{x})^2}{(\sqrt{x})^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}}}\implies \cfrac{x}{x^2+1}\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{\sqrt{x}}{2x^2+2}$

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1 year ago