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erik [133]
3 years ago
10

Given the graph of a line y=−x. Write an equation of a line (there are many) which intersects the line, but is not perpendicular

.
Mathematics
1 answer:
BaLLatris [955]3 years ago
5 0
This would be any equation whose slope isn’t -1 or 1.

If the slope was -1, the lines would be parallel because the have the same slope.

If the slope was 1, the lines would be perpendicular because 1 is the negative reciprocal of -1.

Any line with any other slope will intersect with y=-x.

Hope this helps!
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In right ∆ABC the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find BC if AD = 8 cm and DH = 4 cm.
alina1380 [7]
Check the picture below.

notice that the triangle ADH, since the segment AL is an angle bisector, meaning  it cuts the angle A in two equal halves, then the triangle ADH is only using half of A.

5 0
3 years ago
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Calculate the distance between the points (-6, 4) and (5, -1). Round to the nearest tenth.
ludmilkaskok [199]
It will be 42 because of the with times the 2nd highest
4 0
3 years ago
A poster is shown below: A rectangle is shown. The length of the rectangle is labeled 12 feet. The width of the rectangle is lab
klemol [59]
It would be 7.5ft by 30ft
Because I just multiplied 12 by 5/2 which is 30
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6 0
3 years ago
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Find the quotient of 48a^4-16a^2-32/8a^2-8
Novay_Z [31]
We know that if we had
8/6=2/2 times 4/3=1 times 4/3=4/3
find common factors in top and obttom
factor
48a^4-16a^2-32=(16)(a-1)(a+1)(3a^2+2)
8a^2-8=8(a-1)(a+1)
so we have
\frac{48a^4-16a^2-32}{8a^2-8} = \frac{(2)(8)(a-1)(a+1)(3a^2+2)}{(8)(a-1)(a+1)}= (\frac{8}{8}) (\frac{a-1}{a-1})( \frac{a+1}{a+1}) ( \frac{(2)(3a^{2}+2)}{1})=(2)(3a^2+2)=6a^2+4


answer is 6a^2+4
5 0
3 years ago
X: 2,4,6,8,10
Morgarella [4.7K]

~Hello There!~

12/2 = 6

24/4 = 6

36/6 = 6

etc.

As you can see, y is always 6 times the value of x.

Therefore, the equation would be y = 6x

Hope This Helps You!

Good Luck :)

Have A Great Day ^_^

- Hannah ❤

8 0
3 years ago
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