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3 years ago

Find a function of the form y=Asin(kx)+C or y=Acos(kx)+C whose graph matches this one:

Mathematics

1 answer:

kumpel [21]3 years ago

4 0

Answer:

y = 4cos((π/5)x) +3

Step-by-step explanation:

The graph shows the peak of the function to be at x=0, so a cosine function is an appropriate choice for the model.

The value of A is half the difference between the minimum and maximum, so is ...

A = (1/2)(7 -(-1)) = 4

The value of C is the average of the maximum and the minimum, so is ...

C = (1/2)(7 +(-1)) = 3

The value of k must be chosen so that for one full period, kx is 2π. We note that one minimum is at -5, and the next is at +5, so the period of this waveform is (5 -(-5)) = 10. Then ...

k·10 = 2π

k = π/5 . . . . . divide by 10 and reduce the fraction

Now, we have all the parameters of our function:

y = 4cos((π/5)x) +3

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mrs_skeptik [129]

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4 years ago

If x2 + y2 = 38 and x - y = 2, then what is x? If there are two possible answers, then enter the larger of the two.

Ket [755]

If x-y=2 then x=2+y

And if you insert that in the first equation

$(2 + y) {}^{2} + y {}^{2} = 38$
$4 + 4y + y {}^{2} + {y}^{2} = 38$
$2y {}^{2} + 4y - 34 = 0$
$y = - 1 + \sqrt{17}$
Or
$y = - 1 - \sqrt{17}$

The first one is bigger so the answer is

$y = - 1 - \sqrt{17}$

7 0

3 years ago

Read 2 more answers

Help me please! i have to redo a quiz, but i need answers, no links

Galina-37 [17]

Answer:

Step-by-step explanation:

This is because it got 2 times bigger

7 0

3 years ago

Guys please HELPP!!!!!!!!!!

MA_775_DIABLO [31]

Answer:

Work out after explanation.

Step-by-step explanation:

Split into a trapezium and triangle so you know the height for the triangle. Then find out the area of the trapezium and triangle using their formula. Then add them together. That should be your answer.

6 0

3 years ago

find three consecutive odd integers such that the sum of the last two is 15 less than 5 times the first

Viefleur [7K]

2n + 1 , 2n + 3 , 2n + 5

____________________________

( 2n + 5 ) + ( 2n + 3 ) = 5 × ( 2n + 1 ) - 15

4n + 8 = 10n + 5 - 15

4n + 8 = 10n - 10

Add both sides 10

4n + 8 + 10 = 10n - 10 + 10

4n + 18 = 10n

Subtract both sides 4n

4n - 4n + 18 = 10n - 4n

18 = 6n

Divide both sides by 6

18 ÷ 6 = 6n ÷ 6

n = 3

_________________________________

Thus that three numbers are :

2(3) + 1 , 2(3) + 3 , 2(3) + 5

6 + 1 , 6 + 3 , 6 + 5

7 , 9 , 11

And we're done ....

3 0

3 years ago