To find the y-intercept: replace x with 0
to find the x-intercept: replace y with 0
x-int:
0 = 10x - 32
32 = 10x
x = 3.2
(3.2, 0)
y-int:
y = 10(0) - 32
y = -32
(0, -32)
<h3>
Answer: y^4 - 2y^3 + 7y^2 + y - 5</h3>
Work Shown:
h(y) = f(y) + g(y)
h(y) = (y^4 - 3y^3 + y - 3) + (y^3 + 7y^2 - 2)
h(y) = y^4 - 3y^3 + y - 3 + y^3 + 7y^2 - 2
h(y) = y^4 + (-3y^3+y^3) + 7y^2 + y + (-3 - 2)
h(y) = y^4 - 2y^3 + 7y^2 + y - 5
This is a fourth degree polynomial (aka quartic).
Since the line is parallel, the same coefficients can be used for x and y. The constant on the right needs to change so that the given point will satisfy the equation.
... 5x - 4y = 5(-8) -4(2) = -40 -8 = -48
Your equation is
... 5x -4y = -48
Answer:
The answer to your question is A = 200.96 u²
Step-by-step explanation:
Data
Radius A = 6
Radius B = 2
π = 3.14
Area = ?
Formula
Area = πr²
Process
1.- Calculate the radius of the large circle
Radius = radius of circle A + radius of circle B
Radius = 6 + 2
Radius = 8
2.- Substitute in the formula
Area = (3.14)(8)²
Area = 3.14(64)
Area = 200.96 u²
Answer:
The y-intercept is the point at which the line crosses the y-axis. Example (b) Graph 6x – 3y = 12. Instead of completing a table of values
