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kkurt [141]
3 years ago
8

-11-(-13) hellpppppooppppop

Mathematics
2 answers:
laiz [17]3 years ago
6 0

Answer:

2

Step-by-step explanation:

we have:

-11-(-13)

-11 +13

2

krok68 [10]3 years ago
5 0

Good evening ,

______

Answer:

-11-(-13)=2

___________________

Step-by-step explanation:

You should note that -(-13) = 13

-11-(-13) = -11 + 13 = (-11) + 13 = 13 +(-11) = 13 - 11 = 2.

:)

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Given f(x)=x^2-2x find f(6)
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Step-by-step explanation:

In the picture, I hope that it's a clear solution.

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2 years ago
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What is the area of a regular hexagon with a side length of 4 m? Enter your answer in the box. Round only your final answer to t
Tanzania [10]
The area of a hexagon is 
A= a^2 (3√3)/2
we replace a with 4
A=41.57
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3 years ago
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A piece of wire 11 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
forsale [732]

Answer:

11 meters

Step-by-step explanation:

First, we can say that the square has a side length of x. The perimeter of the square is 4x, and that is how much wire goes into the square. To maximize the area, we should use all the wire possible, so the remaining wire goes into the triangle, or (11-4x).

The area of the square is x², and the area of an equilateral triangle with side length a is (√3/4)a². Next, 11-4x is equal to the perimeter of the triangle, and since it is equilateral, each side has (11-4x)/3 length. Plugging that in for a, we get the area of the equilateral triangle is

(√3/4)((11-4x)/3)²

= (√3/4)(11/3 - 4x/3)²

= (√3/4)(121/9  - 88x/9 + 16x²/9)

= (16√3/36)x² - (88√3/36)x + (121√3/36)

The total area is then

(16√3/36)x² - (88√3/36)x + (121√3/36) + x²

= (16√3/36 + 1)x² -  (88√3/36)x + (121√3/36)

Because the coefficient for x² is positive, the parabola would open up and the derivative of the parabola would be the local minimum. Therefore, to find the maximum area, we need to go to the absolute minimum/maximum points of x (x=0 or x=2.75)

When x=0, each side of the triangle is 11/3 meters long and its area is

(√3/4)a² ≈ 5.82

When x=2.75, each side of the square is 2.75 meters long and its area is

2.75² = 7.5625

Therefore, a maximum is reached when x=2.75, or the wire used for the square is 2.75 * 4 = 11 meters

3 0
3 years ago
Can someone tell me what 2 to the power of 6 is
Ira Lisetskai [31]

{2}^{6}  = 64 = 2 \times 2 \times 2 \times 2 \times 2 \times 2
8 0
3 years ago
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Please give me an answer with an explanation.
Verdich [7]

Answer:

40 and 10

Step-by-step explanation:

1. if the length is 'l' and height is 'h', then according to the condition 1/4*l=h.

2. if the given area is 400, it means, h*l=400;

3. if to substitute h=1/4*l into the formula of the area, then

l*l*1/4=400; ⇔ 1/4*l²=400;

4. if to calculate the value of the 'l', then l=40 (the required length).

5. if to substitute l=40 into 1/4*l=h, then h=10 (the required height).

5 0
3 years ago
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