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Mama L [17]
3 years ago
9

Jeremy is saving $250 per month for his vacation. How much will Jeremy have saved up for his vacation in 1 year and 6 months?

Mathematics
2 answers:
algol [13]3 years ago
6 0

Answer:

Jeremy saved up $4,500.

Step-by-step explanation:

Jeremy is saving $250 per month. 1 year and 6 months is equal to 18 months, so we multiply 250 by 18. 250 x 18 = 4,500.

Hope this helps!

vodka [1.7K]3 years ago
5 0
Jeremy would have saved 4,500
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6 - 8x = 5x - 10x + 12<br> Please help I suck at math thank you
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Answer:

I guess it's -2

Step-by-step explanation:

6-8x = 5x - 10x + 12

∴ 10x - 8x - 5x = 12 - 6

∴ 10x- 13x = 6

∴ - 3x = 6

∴ x = -6\3

∴ x = -2

3 0
2 years ago
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Y^3-27=9y^2-27y how to factor
Kryger [21]
Hello! And thank you for your question!

First we are going to redo the equation:

<span><span><span>y<span><span>​^3</span><span>​​</span></span></span>−3<span>y^<span><span>​2</span><span>​​</span></span></span>(3)+3(y)×<span>3<span><span>​^2</span><span>​​</span></span></span>−<span>3<span><span>​^3</span><span>​​</span></span></span>=0

Then we are going to use Cube of Difference:

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That take cube root of both sides:

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Finally add 3 to both sides:

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Final Answer:

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3 years ago
An urn contains 5 red balls and 2 green balls. Two balls are drawn one after the other. What is the probability that the second
AleksAgata [21]

Answer:

<em>The probability that the second ball is red is 71%</em>

Step-by-step explanation:

<u>Probabilities</u>

We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).

The first ball can be red (R) or green (G). The probability that it's red is computed by

\displaystyle P(R)=\frac{5}{7}

The probability is's green is computed by

\displaystyle P(G)=\frac{2}{7}

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

\displaystyle P(RR)=\frac{5}{7}\cdot \frac{4}{6}=\frac{10}{21}

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

\displaystyle P(GR)=\frac{2}{7}\cdot \frac{5}{6}=\frac{5}{21}

The total probability of the second ball being red is

\displaystyle P(XR)=\frac{10}{21}+\frac{5}{21}=\frac{5}{7}=0.71

The probability that the second ball is red is 71%

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Step-by-step explanation:

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