Ask question

Ask question

All categories

evablogger [386]

3 years ago

10

A large cheese pizza costs $18. Each topping you add on costs $1.50. How much would it cost to get a large cheese pizza with cc

toppings added? Write your answer as an expression

1 answer:

grigory [225]3 years ago

7 0

Answer:

$\$18+\$1.50c$

Step-by-step explanation:

Let

y------> the total cost

c-----> the number of topping

we know that

$y=\$18+\$1.50c$ ----> linear equation that represent the situation

You might be interested in

What the 50th term to question two part be

Likurg_2 [28]

Answer:

290

Answer: The 50th term of the sequence is 290.

6 0

2 years ago

Jenna has at most $80 to spend on clothes. She wants to buy a pair of jeans for$22 and spend the rest on t-shirts. Each t-shirt

weqwewe [10]

Answer:

7 shirts

Step-by-step explanation:

You first have to subtract 22 from 80, since that's how much she already spent, 80-22=58. Now you have to do 58/8, but since 8 doesn't divide evenly into 58, you have to go with the closet multiple of 8 which would be 56. 7x8=56, so Jenna can buy a maximum number of 7 shirts.

5 0

2 years ago

Factor the mn+5m-3n-15

neonofarm [45]

The factor of mn+5m-3n-15 is 6m-4n-15.

3 0

2 years ago

Describe the end behaviors of the following function:

Vika [28.1K]

Answer:

6

Step-by-step explanation:

momgdhdfhgdeiijjjjgtrr

3 0

2 years ago

Solve the quadratic equation by completing the square.<br> x²–2x-12=0

inn [45]

Answer:

$(x-1)^2-13=0$

$x = \sqrt{13}+1$

Step-by-step explanation:

Completing the square is a method of rewriting a quadratic equation in the standard form such that it is in vertex form. The first step is to group the linear and quadratic terms, then factor out the coefficient of the quadratic term. After doing so, complete the square, add a value such that the linear and quadratic terms form a perfect square trinomial. Do not forget to balance the equation. The final step is to simplify.

$x^2-2x-12=0$

Group,

$(x^2-2x)-12=0$

Complete the square,

$(x^2-2x+1)-12-1=0$

Simplify,

$(x-1)^2-13=0$

Now solve the equation using inverse operations,

$(x-1)^2-13=0\\\\(x-1)^2=13\\\\x-1=\sqrt{13}\\\\x = \sqrt{13}+1$

7 0

2 years ago