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NeX [460]
3 years ago
14

You brought 1.5 dozen bagels to school. A dozen bagels cost $5.98. You used a coupon that took $1.00 off of the total. How much

did you pay for the bagels?
Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
6 0
1 Dozen = 12
1 Dozen = $5.98
1/2 Dozen = 6
1/2 Dozen = $2.99

Add 1 Dozen ($5.98) and 1/2 Dozen ($2.99) Which Equals= $8.97 then subtract the $1.00 Coupon So final answer is $7.97 for 1.5 dozen bagels.
erik [133]3 years ago
5 0

Answer: He would pay $7.97 for the bagel.

Step-by-step explanation:

Since we have given that

Number of dozen bagels he brought to school = 1.5

Cost of a dozen = $5.98

Total cost of 1.5 dozen bagels he brought to school is given by

1.5\times 5.98\\\\=\$8.97

According to question, he used a coupon that took $1.00 off of the total .

so, it becomes

\$8.97-\$1.00\\\\=\$7.97

Hence, he would pay $7.97 for the bagel.

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There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
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Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

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Z = \frac{X - \mu}{\sigma}

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You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
3 years ago
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