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3 years ago

Please answer this correctly

Mathematics

2 answers:

belka [17]3 years ago

6 0

Answer:

v = 50

Step-by-step explanation:

The trapezoids are similar, so set up a proportion like so:

$\frac{56}{v} =\frac{84}{75}$

→Cross multiply:

$\frac{4200}{84v}$

→Divide 4200 by 84:

v = 50

natita [175]3 years ago

5 0

Answer:

50 km

Step-by-step explanation:

As the figures are given similar ,

56/v = 84/75

v = 56 × 75/84

v = 50 km

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Suppose there was a cancer diagnostic test was 95% accurate both on those that do and those do not have the disease. If 0.4% of

Musya8 [376]

Complete Question

Suppose there was a cancer diagnostic test was 95% accurate both on those that do and 90% on those do not have the disease. If 0.4% of the population have cancer, compute the probability that a particular individual has cancer, given that the test indicates he or she has cancer.

Answer:

The probability is $P(C | A) = 0.0042$

Step-by-step explanation:

From the question we are told that

The probability that the test was accurate given that the person has cancer is

$P(A | C) = 0.95$

The probability that the test was accurate given that the person do not have cancer is

$P(A | C') = 0.90$

The probability that a person has cancer is

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Generally the probability that a person do not have cancer is

$P(C') = 1- P(C)$

=> $P(C') = 1- 0.004$

=> $P(C') = 0.996$

Generally the probability that a particular individual has cancer, given that the test indicates he or she has cancer is according to Bayes's theorem evaluated as

$P(C | A) = \frac{P(A | C) * P(C)}{P(A|C) * P(C) + P(A| C') * P(C')}$

=> $P(C | A) = \frac{ 0.95 * 0.004 }{ 0.95 * 0.004 + 0.90 * 0.996}$

=> $P(C | A) = 0.0042$

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3 years ago

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valentina_108 [34]

Answer:

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Step-by-step explanation:

Given

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Answer:

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