A kilogram of silver contains 5.58×10²⁴ atoms.
<h3>How to determine the parameter</h3>
From the question given above, the following data were obtained:
- 1 mole of silver = 107.9 g
- Number of atoms in 1 mole of silver = 6.02×10²³ atoms.
- Number of atoms in a kilogram of silver is unknown
Now, we shall convert 1 kg of silver to grams (g).
This can be obtained as follow:
1 kg = 1000g
Therefore, 1 kg of silver is equivalent to 1000g.
Now, let's determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:
If 107.9 g of silver contains 6.02×10²³ atoms.
Then, 1000 g of silver will contain:
= (1000 × 6.02×10²³) / 107.9
= 5.58×10²⁴ atoms.
Thus, a kilogram of silver contains 5.58×10²⁴ atoms.
Learn more about atoms here:
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Answer:
Step-by-step explanation:
Slope-intercept form looks like this: y = mx + b (m is the slope value).
As you can see from the slope-intercept form, the "y" needs to be on a side alone, so move all other values to the other side.
-5y = -2x - 15 --> Not, divide the -5 off the "y".
y = 2/5x + 3
Therefore, your equation in slope-intercept form is y = 2/5x + 3
Answer:
40 gold notebooks
Step-by-step explanation:
5:3 gold notebooks to red notebooks so using this we can set up a proportion
5 x
-- = ---
3 24
cross multiplying
3x = 120
x= 40
so there are 40 gold notebooks if there are 24 red notebooks