Consider the reaction 2x2y2+z2⇌2x2y2z which has a rate law of rate= k[x2y2][z2] select a possible mechanism for the reaction.

-3 is the value of the location where the line crosses the y-axis,and is commonly referred in the slope-intercept form of a line "the intercept". Now it may be your teacher expects you to answer this as the point on the plane where the y-intercept occurs, and that should be the point (0, -3). Make sure you follow your teacher's notation.

Step-by-step explanation:

Re-write the equation given in slope=intercept form by isolating the variable "y" on one side of the equation and expressing the rest in slope*x + y-intercet form:

$-2y-4x-6=0\\-4x-6=2y\\y=-2x-3\\$

which tells us that the slope of the line is -2 and it y-intercept is "-3".

Now, watch out because you may be asked to write the actual coordinates of the y-intercept, which are: (0, -3)

giving the x-coordinate 0 and the y-value where the line crosses the y-axis.

7 0

3 years ago

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A car is traveling at 47 mph. If its tires have a diameter of 27 inches, how fast are the car's tires turning? Express the answe

Amiraneli [1.4K]

Answer:

3676.44 rad/min

Step-by-step explanation:

It is a problem about the angular speed of the car's wheel.

You can calculate the angular speed by using the following formula, which relates the tangential speed of the wheels (the same as the speed of the car) with the angular speed:

$\omega=\frac{v}{r}$ ( 1 )

v: speed of the car = tangential speed of the wheels = 47mph

r: radius of the wheels = 27/2 in = 13.5 in

you change the units of the speed:

$47mph*\frac{63360in}{1mille}*\frac{1h}{60min}=49632\frac{in}{min}$

next, you replace the values of v and r in the equation (1):

$\omega=\frac{v}{r}=\frac{49632in/min}{13.5in}=3676.44\frac{rad}{min}$

Then, the car's tires are turning with an angular speed of 3676.44 rad/min

8 0

3 years ago