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OlgaM077 [116]
4 years ago
6

What are the solutions of the equation?

Mathematics
1 answer:
Maksim231197 [3]4 years ago
3 0

Answer:

x₁ = √15

x₂ = - √15

Step-by-step explanation:

x² - 15 = 0

x² = 15

x = ±√15

x₁ = √15

x₂ = - √15

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The product of a number and -6 is -600
rewona [7]

Answer:

n= 100

Step-by-step explanation:

Product is the answer when two numbers are multiplied together. So, n×-6=600.

100×-6=-600

3 0
4 years ago
there are 3 good guys and three bad guys on one side of a river full of piranhas and there is a canoe big enough for two people
labwork [276]
If there are 3 bad guys and 3 good guys then they don't out number the good guys.
4 0
3 years ago
Evaluate f(x) = x2 – 12 when x = 5
Ede4ka [16]

Answer:

f(5) = 13

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Function notation and substitution

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 12

x = 5

<u>Step 2: Evaluate</u>

  1. Substitute:                   f(5) = 5² - 12
  2. Exponents:                  f(5) = 25 - 12
  3. Subtract:                      f(5) = 13
4 0
3 years ago
Read 2 more answers
A school debate team has four girls and six boys. A total of four of the team members will be chosen to participate in the distr
alex41 [277]
Procedure:

1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)

Solution

1) the number of teams of four members that can be formed are:

10*9*8*7 / (4*3*2*1) = 210

2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls

Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6

Number of different teams with 2 boys and 2 girls = 15 * 6 = 90

3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:

90/210 = 3/7
 
7 0
3 years ago
Proof true or false: For all integers a,b,and c,if ab|c then a|c and b|c
olya-2409 [2.1K]

Answer with explanation:

It is given that for three integers , a, b and c, if

              \frac{ab}{c}\rightarrow then, \frac{a}{c} \text{or} \frac{b}{c}

Since , a b is divisible by c , following are the possibilities

1.→ a and b are prime integers .Then , c will be prime number either equal to a or b.

2.→a and b are not prime integers ,then any of the factors of a or b will be equal to c.For example:

 ⇒a=m × n

 b=p × q× c

or,

⇒a=u×v×c

b=s×t

So, whatever the integral values taken by a, and b, if \frac{ab}{c} then either of  \frac{a}{c} \text{or} \frac{b}{c} is true.

4 0
3 years ago
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