Solution :
First term, a₀ = -10 .
Common difference of A.P. , d = -8 - (-10) = 2 .
Last term, aₙ = 24 .
We know, last term is given by :
aₙ = a₀ + (n-1)d
24 = -10 + (n-1)×2
2n - 2 = 34
n = 18
Now, sum of series is given by :

Hence, this is the required solution.
Answer:
![\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D)
x ^( 1/8)
Step-by-step explanation:
x ^ (5/6) ÷ x ^ (1/6)
We know that a^ b ÷ a ^c = a^ ( b-c)
x^ ( 5/6 - 1/6)
x^ (4/6)
x ^ 2/3
![\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D)

![\sqrt[\\4]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5C%5C4%5D%7Bx%7D)
x ^ 1/2 * x ^ 1/4
We know that a^ b * a ^ c = a^ (b*c)
x ^ (1/2 * 1/4)
x ^( 1/8)
f(x) = -37
Domain is all real numbers

Range is only {-37}

Answer:
the answer is 0 because both equations on either side cancel out thereby leaving in bare