A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.
Answer:
arc FD = 236°
Step-by-step explanation:
The measure of the arc is equal to the measure of the central angle it subtends, thus
arc FD = arc FE + arc ED = 146° + 90° = 236°
Answer:
(x-6) (x-4)
Step-by-step explanation:
x^2 - 10x + 24
What 2 numbers multiply to 24 and add to -10
-6*-4 = 24
-6+-4 = -10
(x-6) (x-4)
Answer:
8 yd
Step-by-step explanation:
The opposite side is 14 and the lower portion plus the missing value would equal 14:
14 = 6 + ?
So subtract 6 from 14 to get the missing length, 8.
Answer:
x = 8
x = -8
Step-by-step explanation: