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3 years ago

Please help with the question above????

Mathematics

2 answers:

Yanka [14]3 years ago

8 0

Answer:

the answer is C

Step-by-step explanation:

if you divide 1by9 1÷9

it will come 0.11111111111111.....

so the answer is C

mark me as brainliest plyyyzzz

Schach [20]3 years ago

4 0

Answer:

its b

Step-by-step explanation:

is b

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Allentown got 2 feet less than twice the amount of snow Georgetown got . Allentown got 3 feet more snow than Georgetown. How man

Mandarinka [93]

x=2y-2

x=y+3

Substitute the second equation into the first

y+3=2y-2

solve for y

y=5

plug into original

x=y+3=5+3=8 or x=2(5)-2=8

Allentown got 8 ft of snow, Georgetown got 5 ft of snow.

4 0

3 years ago

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20 points...<br><br> Sherlock - please help!

antiseptic1488 [7]

Answer:

C) $\{\frac{1+\sqrt{5}}{3},\:\frac{1-\sqrt{5}}{3}\}$

Step-by-step explanation:

$(3x-1)^2=5\\\\3x-1=\pm\sqrt{5}\\\\3x=1\pm\sqrt{5}\\\\x=\frac{1\pm\sqrt{5}}{3}\\ \\\{\frac{1+\sqrt{5}}{3},\:\frac{1-\sqrt{5}}{3}\}$

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2 years ago

This composite figure is made up of three simpler shapes. What is the area of the figure? 7 cm 4 cm 5 cm 4 CE 8 cm A. 66 square

kirza4 [7]

The total area of the given figure will be 66 square cm.

The space occupied by any two-dimensional figure in a plane is called the area. Here we have three shapes a triangle, a rectangle and a parallelogram.

Total area = Area of triangle + Area of rectangle + Area of parallelogram

Total area = [(1/2) x 4 x7] + [4 x 5] + [ 4 x 8 ]

Total area = 14+20+32

Total area = 66 square cm

Hence the total area of the given figure will be 66 square cm.

To know more about the area follow

brainly.com/question/24375372

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2 years ago

Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter

Vaselesa [24]

We have been given a function $f(x)=2x^3+3x^2-336x$ . We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

$f'(x)=2(3)x^{2}+3(2)x^1-336$

$f'(x)=6x^{2}+6x-336$

$6x^{2}+6x-336=0$

$x^{2}+x-56=0$

$x^{2}+8x-7x-56=0$

$(x+8)-7(x+8)=0$

$(x+8)(x-7)=0$

$x=-8,x=7$

So $x=-8,7$ are critical points and these will divide our function in 3 intervals $(-\infty,-8)U(-8,7)U(7,\infty)$ .

Now we will find derivative over each interval as:

$f'(x)=(x+8)(x-7)$

$f'(-9)=(-9+8)(-9-7)=(-1)(-16)=16$

Since $f'(9)>0$ , therefore, function is increasing on interval $(-\infty,-8)$ .

$f'(x)=(x+8)(x-7)$

$f'(1)=(1+8)(1-7)=(9)(-6)=-54$

Since $f'(1)$ , therefore, function is decreasing on interval $(-8,7)$ .

Let us check for the derivative at $x=8$ .

$f'(x)=(x+8)(x-7)$

$f'(8)=(8+8)(8-7)=(16)(1)=16$

Since $f'(8)>0$ , therefore, function is increasing on interval $(7,\infty)$ .

(b) Since $x=-8,7$ are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

$f(-8)=2(-8)^3+3(-8)^2-336(-8)$

$f(-8)=1856$

$f(7)=2(7)^3+3(7)^2-336(7)$

$f(7)=-1519$

Therefore, $(-8,1856)$ is a local maximum and $(7,-1519)$ is a local minimum.

Let us find 2nd derivative.

$f''(x)=6(2)x^{1}+6$

$f''(x)=12x+6$

$12x+6=0$

$12x=-6$

$\frac{12x}{12}=-\frac{6}{12}$

$x=-\frac{1}{2}$

Therefore, $x=-\frac{1}{2}$ is an inflection point of given function.

3 0

3 years ago

Describe the error in the work below.

Agata [3.3K]

If u take you answer as x and do the problem u will see that they are equal so u would have to have a different answers for x or say -6.1 is greater than or equal to -17.4 + 11.3

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3 years ago

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