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xz_007 [3.2K]
3 years ago
7

Which sentence correctly describes a data set that follows a normal distribution with a standard deviation of 4 and a mean of 14

?
A. 68% of the data points lie between 10 and 14.
B. 68% of the data points lie between 8 and 12.
C. 6896 of the data points lie between 10 and 18.
D. 68% of the data points lie between 10 and 16.
Mathematics
1 answer:
denis-greek [22]3 years ago
4 0

Answer:

Option (c) is correct.

68% of the data points lie between 10 and 18.

Step-by-step explanation:

Given :  a normal distribution with a standard deviation of 4 and a mean of 14

We have to choose the  sentence that correctly describes a data set that follows a normal distribution with a standard deviation of 4 and a mean of 14.

Since, given 68% data.

We know mean of data lies in middle.

And standard deviation is distribute equally about the mean that is 50% of values less than the mean  and 50% greater than the mean.

So, 68% of data lies

mean - standard deviation = 14 - 4 = 10

mean + standard deviation = 14 + 4 = 18

So, 68% of the data points lie between 10 and 18.

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Answer:

p_v =2*P(t_{(35)}  

Step-by-step explanation:

Assuming this info from R

hist(gifted$count)

##    Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

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## Sd

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Data given and notation  

\bar X=30.69 represent the mean  

s=4.3149 represent the sample standard deviation

n=36 sample size  

\mu_o =32 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different than 32, the system of hypothesis would be:  

Null hypothesis:\mu = 32  

Alternative hypothesis:\mu \neq 32  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{30.69-32}{\frac{4.3149}{\sqrt{36}}}=-1.822    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=36-1=35  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(35)}  

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