You are given the equation 36 = 9x² + 4y². You are asked to find the slopes of the asymptotes of the hyperbola. A hyperbola has the following general equation x²/a² + y²/b² = 1. the goal here is to find the slopes of the hyperbolic equation. So divide both sides by 36
36 = 9x² + 4y²
(1/36)[36 = 9x² + 4y²]
1 = x²/4 + y²/9
a² = 4
a = 2
and
b² = 9
b = 3
To find the slope, divide a/b and you will get 2/3.
The answer is 0.3413 because Explanation:
<span>z=<span><span>x−u</span>σ</span></span>, where <span>u=6 0andσ=10</span>.
Therefore the probability student finish the test between 50 to 60 minutes is,
<span>P<span>(50≤x≤60)</span>=P<span>(<span><span>50−60</span>10</span>≤z≤<span><span>60−60</span>10</span>)</span></span>
<span>P<span>(−1≤z≤0)</span>=P<span>(z≤0)</span>−P<span>(z≤−1)</span></span>
<span>=0.5000−0.1587=<span>0.3413</span></span>
Answer:
y=3/2and x =2
Step-by-step explanation:
Answer:
Using Pythagorean theorem:
Diagonal = sqrt( 60^2 + 100^2) = 116.62
Hope this helps!
:)
