Hello,
6b) (i) As you can see, in the first year the price drops from 27,000 to 17,000. (Look at year 0-1 on the x axis). To find the percentage drop, find the difference between the two values and divide it over the initial value of 27,000.
So, the percentage drop in the first year is:
(27000-17000) / (27000) = 0.37, or a 37% drop
The answer is 37%.
(ii) For this question, we basically have the same process as the previous question except for the second year.
From year 1 to year 2, the value starts at 17,000 and ends at 15,000.
To find the percentage drop, we do:
(17000 - 15000) / (17000) = 0.118 ≈ 0.12, or a 12% drop
The answer is 12%.
6c) To find the percentage depreciation over the first 5 years, we look at the initial value (x = 0) and the value after 5 years (x = 5), and use these values in the same percentage formula we have been using.
The initial value of the car is 27,000, and after 5 years the value is 8,000.
This is a percentage drop of (27000 - 8000) / (27000) = 0.70, or a 70% drop.
The answer is 70%.
Hope this helps!
Answer:
k = 10
Step-by-step explanation:
The sum of k terms of a geometric sequence with first term a1 and common ratio r is given by ...
... Sk = a1·(1 -r^k)/(1 -r)
For the given numbers, this is ...
... 118096 = 78732·(1 -(1/3)^k)/(1 -1/3)
Manipulating this to get the term containing k, we have
... 1 -(2/3)(118096/78732) = (1/3)^k
... 1/59049 = (1/3)^k
Taking logarithms, we get
... -log(59049) = -k·log(3)
... log(59049)/log(3) = k = 10
if the sequence goes on without any changes
it will be d+8a
Answer:
The answer would be 2012 and 2004
Step-by-step explanation:
when you round 30.346 to the nearest tenth it is 30.4 and when you round 30.406 to the nearest tenth then it is also 30.4.
Hope it helps!
:)
Answer:
I got 70% hope it helps man
