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3 years ago

Perimeter of rectangle 11=2(l)+2(3/2)

Mathematics

2 answers:

kykrilka [37]3 years ago

5 0

Answer:

4+6(2/4)

Step-by-step explanation:

3/2 is going to turn that two into a 3 and the you add 2+2

3(1/2) + 3(1/2) to get six

4 plus 6 is 10

then add the two halves to make 1

thus your answer is 11

avanturin [10]3 years ago

4 0

Answer:

Step-by-step explanation:

If the perimeter is 11, then P = 11 = 2(length) + 2(width).

Here we have 11 = 2(length) + 2(3/2), or

11 = 2 length + 3.

Solving for "length," we subtract 3 from both sides:

8 = 2(length), or

length = 4

Thus, if the perimeter is 11 and the width is 3/2 (as given), the length must be 4.

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Answer:

$z=\frac{0.579 -0.67}{\sqrt{\frac{0.67(1-0.67)}{38}}}=-1.193$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.1$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the proportion of women athletes graduated is not significantly lower than 0.67 or 67% at 10% of significance

Step-by-step explanation:

Data given and notation

n=38 represent the random sample taken

X=22 represent the number of women athletes graduated

$\hat p=\frac{22}{38}=0.579$ estimated proportion of women athletes graduated

$p_o=0.67$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is lower than 0.67 or no:

Null hypothesis: $p \geq 0.67$

Alternative hypothesis: $p < 0.67$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.579 -0.67}{\sqrt{\frac{0.67(1-0.67)}{38}}}=-1.193$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

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Read 2 more answers