An integer may be a multiple of 3.
An integer may be 1 greater than a multiple of 3.
An integer may be 2 greater than a multiple of 3.
It is redundant to say an integer is 3 greater than a multiple of 3 (that's just a multiple of 3, we've got it covered). Same for 4, 5, 6, 7...
Let's consider a number which is a multiple of 3. Clearly, we can write 3+3+3+3+... until we reach the number. It can be written as only 3's.
Let's consider a number which is 2 greater than a multiple of 3. If we subtract 5 from that number, it'll be a multiple of 3. That means we can write the number as 5+3+3+3+3+... Of course, the number must be at least 8.
Let's consider a number which is 1 greater than a multiple of 3. If we subtract 5 from that number, it'll be 2 greater than a multiple of 3. If we subtract another 5, it'll be a multiple of 3. That means we can write the number as 5+5+3+3+3+3+... Of course, the number must be at least 13.
That's it. We considered all the numbers. We forgot 9, 10, 11, and 12, but these are easy peasy.
Beautiful question.
Answer:
2i, if you don't understand any of the steps let me know, I'd be happy to explain.
Step-by-step explanation:
so in order -4 = -1 * 4 so then 
then just solve each
Answer:
the answer to this is b( 2,-8)
Answer:
5x-3p
Step-by-step explanation:
(1/3)(3x-6p) + 4x - p
Distribute the 1/3 to the variables in parenthesis.
x - 2p +4x - p
Combine the like variables.
5x - 3p
Hope this helps!
