All categories

3 years ago

how do you write these equations in slope-intercept form y+1=2x-3 ,2x-3=y+1 , 2y+2=4x-6. Are they the same or different?

Mathematics

1 answer:

inna [77]3 years ago

8 0

y+1=2x-3

y=2x-4

2x-3=y+1

2x-4=y

y=2x-4

2y+2=4x-6

2y=4x-8

y=2x-4

They are all the same: y=2x-4

You might be interested in

Which is greater 50 Hectoliters or 10 kiloliters

Tomtit [17]

Kiloliters are bigger so if they are bigger they have to be kiloliters right>:)
10kL = 100hL, so 10kL > 50hL

6 0

3 years ago

Helpppppppp??????????

Alexxx [7]

Answer:

Answer is option d

Answer is given below with explanations.

Step-by-step explanation:

We can prove that the two triangles are similar.

We can prove this using AA criterion of similarity.

In triangle DNC and triangle QSC

Vertically opposite angles are equal.

Then Angle QCS = Angle DCN

Two parallel lines cut by a transversal line make the alternate angles are equal.

Then Angle NDC = Angle CQS

By AA criterion of similarity

TRIANGLE DNC ~ TRIANGLE QSC

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

8 0

3 years ago

Read 2 more answers

Can someone help me its urgent:( ??

wariber [46]

Answer:

see the procedure

Step-by-step explanation:

Identify

Let

x ---> the cost of the Xbox one at Walmart

Strategy

we know that

The cost of the Xbox one at Walmart multiplied by 2 plus $50 must be equal to $450

Set up

The algebraic expression that represent this situation is

$450=2x+50$

Solve

solve for x

$450=2x+50$

$2x=450-50\\2x=400\\x=\$200$

Check

substitute the value of x in the equation

$450=2(200)+50$

$450=450$ ----> is ok

6 0

3 years ago

The following are the ages (years) of 5 people in a room: 14, 16, 16, 13, 23 A person enters the room. The mean age of the 6 peo

myrzilka [38]

Answer:

44.

Step-by-step explanation:

Since the mean of 14, 16, 16, 13, 23, x is 21, then we have 14 + 16 + 16 + 13 + 23 + x is equal to 126. Summing we have 14 + 16 + 16 + 13 + 23 = 82. 82 + x is equal to 126. X = 44.

4 0

3 years ago

Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(0) = 2.8 y(t) = 0 Preview

mario62 [17]

Answer: The required solution is

$y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$5y^{\prime\prime}+3y^\prime-2y=0,~~~~~~~y(0)=0,~~y^\prime(0)=2.8~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$5m^2e^{mt}+3me^{mt}-2e^{mt}=0\\\\\Rightarrow (5m^2+3y-2)e^{mt}=0\\\\\Rightarrow 5m^2+3m-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow 5m^2+5m-2m-2=0\\\\\Rightarrow 5m(m+1)-2(m+1)=0\\\\\Rightarrow (m+1)(5m-1)=0\\\\\Rightarrow m+1=0,~~~~~5m-1=0\\\\\Rightarrow m=-1,~\dfrac{1}{5}.$

So, the general solution of the given equation is

$y(t)=Ae^{-t}+Be^{\frac{1}{5}t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-Ae^{-t}+\dfrac{B}{5}e^{\frac{1}{5}t}.$

According to the given conditions, we have

$y(0)=0\\\\\Rightarrow A+B=0\\\\\Rightarrow B=-A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

and

$y^\prime(0)=2.8\\\\\Rightarrow -A+\dfrac{B}{5}=2.8\\\\\Rightarrow -5A+B=14\\\\\Rightarrow -5A-A=14~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (ii)}]\\\\\Rightarrow -6A=14\\\\\Rightarrow A=-\dfrac{14}{6}\\\\\Rightarrow A=-\dfrac{7}{3}.$

From equation (ii), we get

$B=\dfrac{7}{3}.$

Thus, the required solution is

$y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.$

7 0

3 years ago