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3 years ago

Let f(x)=x2+15x+56

Mathematics

2 answers:

Ivan3 years ago

6 0

Answer:

-8, -7

Step-by-step explanation:

f(x)=x^2+15x+56

0 =x^2+15x+56

What two numbers multiply together to make 56 and add together to 15

7*8 = 56

7+8=15

0 = (x+8) (x+7)

Then use the zero product property

x+8 =0 x+7 =0

x+8-8 =0-8 x+7-7 =0-7

x=-8 x=-7

kvv77 [185]3 years ago

6 0

Answer:

-7 , -8

Step-by-step explanation:

x² + 15x + 56 = 0

x² + 7x + 8x + 56 = 0

x(x + 7) + 8(x + 7) = 0

(x + 7)(x + 8) = 0

x = -7 , -8

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Answer:

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Step-by-step explanation:

We are given that two real numbers

squareroot of 7 and 14/5

We have to compare the given two real numbers and fill the mathematical symbol in the blank

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Value of squareroot of 7 = 2.646

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Value of 2.645 is less than 2.8.

Hence, squareroot of 7 is less than 14/5

hope i helped! :D

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$\large \underline{ \mathbb{QUESTION:}}$

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$\large\underline{ \mathbb{ANSWER \: \& \: SOLUTION:}}$

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