So assuming that the total =27
r+b=27
r=-5+3b
r=3b-5
subsitute 3b-5 for r in first equation
3b-5+b=27
4b-5=27
add 5
4b=32
divide by 4
b=8
subsitute
b+r=27
8+r=27
subtracct 8
r=19
red=19
blue=8
Hexagon is a total of 6 triangle
Let find area of one triangle the multiplying with 6
Area of a triangle is A=1/2bh
We know b=6 and h= (6(square root of 3))/2
A= 1/2x6x(6(square root of3))/2=9(square root of 3)
Where square root of 3= 1.732
Area of a triangle=9x1.732 =15.588
Area of Hexagon equals 6 area of triangle so
Area of Hexagon= 6x 15.588=93.53
Answer:
Answer choice C) 3a-3
Step-by-step explanation:
Your perimeter is of (10a-6). The first step would be multiply 2a by 2 since you have to sides. Which would give you to 4a. Next you will have to subtract 4a from (10a-6). This would give you 6a-6. Finally divide by two and you will get 3a-3.
Replace all x with -3
f(-3)=(-3)^2+2(-3)
f(-3)=9-6
f(-3)=3
