Question

An engineering school reports that 53% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A), and that 21% were both male and between the ages of 18 and 20. What is the probability of choosing a random student who is a female or between the ages of 18 and 20? Assume P(F) = P(not M). Your answer should be given to two decimal places.

Answer 1

Answer: Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

                      18-20                  Not 18-20           Total

Male                0.23                    0.35                 0.58

Female            0.16                     0.26                0.42

Total                0.39                    0.61                   1

P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)

P(female or between 18-20) =  0.42+0.39-0.16

P(female or between 18-20) = 0.65

Hence, our required probability is 0.65.