Given:
Sample mean = 65.4
Standard deviation = 1.2
Sample size = 45
Confidence level = 99%
To find:
The confidence interval.
Solution:
The formula for confidence interval is
where, 
is sample mean, z* is confidence value, s is standard deviation and n is sample size.
Confidence value or z-value at 99% = 2.58
Putting the given in the above formula, we get
Therefore, the correct option is D.
HCF= highest common factor
LCM= least common multiple
Answer:
30-100
28-100
25-100
7-100
Step-by-step explanation:
It's hard to explain but I try
part in this means how many seeds we can place in those parts
and the whole it he whole amount of the part
hope that make sense
Largest 5-digit number is 54312 and is divisible by 6. The smallest 5 digit number is 12,345 and it's not divisible by 6
So a times 10^n where 1≤|a|<10 and n is an integer is what i learned
so
a.
234=
2.34 times 100=
2.34 times 10²
b.
0.000052=
5.2 times 1/100000=
5.2 times 10⁻⁵
c.
-220000=
-2.2 times 100000=
-2.2 times 10⁵
d. ok, so just count the spaces moved to the left
-18.2 times 10⁻¹⁵
