Using exponential functions, it is found that:
a) Since the <u>amount of caffeine will be less than 50 mg</u>, the patient will be ready for the blood test by 6 a.m.
b) The patient could have ingest 231 milligrams of caffeine.
A decaying <em>exponential function</em> is modeled by:

In which:
- A(0) is the initial value.
- r is the decay rate, as a decimal.
In this problem:
- Caffeine metabolize at a rate of 13% per hour, hence
.
Then:



Item a:
The coffee cup contains 150 milligrams of caffeine, hence
.
At 6 a.m., it is 8 hours after drinking the coffee, hence we have to find A(8).



Since the <u>amount of caffeine will be less than 50 mg</u>, the patient will be ready for the blood test by 6 a.m.
Item b:
This A(0), considering <u>A(11) = 50</u>, hence:



The patient could have ingest 231 milligrams of caffeine.
A similar problem is given at brainly.com/question/25537936
2x^2+20x=-38 divide both sides by 2
x^2+10x=-19, halve the linear coefficient, square it, than add that value to both sides of the equation, in this case add (10/2)^2=25...
x^2+10x+25=6 now the left side is a perfect square
(x+5)^2=6 take the square root of both sides
x+5=±√6 subtract 5 from both sides
x=-5±√6 (so answer c.)
Answer:
0.301
Step-by-step explanation:
Given that log 3 = .477 and log 6 =.778
Log 2
= log(6/3)
= log 6 - log 3
= 0.778 - 0.477
= 0.301
Hence the value of log 2 is 0.301