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denis-greek [22]

3 years ago

5

Jesse uses 2 pounds of fertilizer for a 100-foot row of vegetables at her farm. At this rate, how many pounds of fertilizer woul

d she use for a 450-foot row of vegetables? Explain.

1 answer:

77julia77 [94]3 years ago

6 0

9 pounds = 2 times 4 plus 1.

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You have 30,016 grams of radioactive kind of

Ostrovityanka [42]

Answer:

15,008 grams

Step-by-step explanation:

You have 30,016 grams of radioactive kind of rubidium. How much will be left after 54 minutes if its half-life is 18 minutes? 15,008 grams.

4 0

2 years ago

Sam is baking 10 pies for a school bake sale. He uses 21 cups of apples for 6 pies. How many cups of apples will he need to make

sertanlavr [38]

Answer:

35

Step-by-step explanation:

6 pies = 21 cups of apples

1 pie = 3.5 cups of apples

10 pies = 35 cups of apples

7 0

2 years ago

Find the length of the arc on a circle of radius r intercepted by a central angle 0. Round answer to

mario62 [17]

Answer:

yes

Step-by-step explanation:

soory i need points

3 0

2 years ago

Factorize 1-(3x-1)^2

solniwko [45]

Step-by-step explanation:

(1+3x-1)×{1-(3x-1)}

=3x.(1-3x+1)

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6 0

3 years ago

Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account

Diano4ka-milaya [45]

Answer:

$\$180.55$

Step-by-step explanation:

step 1

<u><em>Simple interest</em></u>

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04$

substitute in the formula above

$A=2,250(1+0.04*10)$

$A=2,250(1.4)$

$A=\$3,150$

step 2

<u><em>Interest compounded annually</em></u>

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1$

substitute in the formula above

$A=2,250(1+\frac{0.04}{1})^{1*10}$

$A=2,250(1.04)^{10}$

$A=\$3,330.55$

step 3

Find the differences between the two final amounts

$A=\$3,330.55-\$3,150=\$180.55$

5 0

3 years ago