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3 years ago

Help n explain pleaseee

Mathematics

2 answers:

wel3 years ago

7 0

Answer:

(3, 7)

Step-by-step explanation:

Just substitute x = 3 into the equations.

2(3) + 4y = 34

6 + 4y = 34

4y = 28

y = 7

natta225 [31]3 years ago

6 0

Answer:

(3,7)

Step-by-step explanation:

does not matter what you put x into so choose one, out come is the same.

2(3)+4y=34

6+4y=34

4y=28

do remove y and the 4 divide both sides by 4

y=7

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Can someone tell me if I did this right? If it's wrong can you tell me how to do it step by step? Thanks

Lesechka [4]

Hi there!

So first off, here are little definitions you need to know in order to be able to answer your question :

<u>Constant</u> means that the rates of change are the same.

<u>Variable</u> means that the rates of change are different.

But from what I can see, you don't even need those definitions because you got both answers right!

Continue your great work! If there's anything just let me know! :)

6 0

3 years ago

Any help greatly appreciated

REY [17]

Answer:

Option B. 8.6%

Step-by-step explanation:

Simple index of two stocks: i=?

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8 0

2 years ago

Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$

So, this integral is divergent.

4 0

3 years ago

The distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on y

kaheart [24]

Answer:

d(1) = -3 and d(2)= -28

Step-by-step explanation:

Given that the distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on your distance x, in meters, from the stabilized point

$d(x)=-4x^3+x^2$