Where’s the picture. Please show it
According to the Triangle inequality theorem, this does not work
For a triangle to be valid, the length of any two sides added together must by greater than the length than the third side.
In this example, we can see that the side with length 1 added to the side with length 2 is equal to 3inches.
3 inches is less that 4inches (the length of the 3rd side). So that triangle does not work.
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Answer
This triangle does not work, because the sum of the lengths of any two sides of a triangle is <u>NOT</u> greater than the length of the third side.
Brown oooOiejdjdjdjdieoeidididieoddo gg 1919912
Well, I'm not completely sure, because I don't know the formal definition
of "corner" in this work. It may not be how I picture a 'corner'.
Here's what I can tell you about the choices:
A). (0, 8)
This is definitely a corner of the feasible region.
It's the point where the first and third constraints cross.
So it's not the answer.
B). (3.5, 0)
This is ON the boundary line between the feasible and non-feasible
regions. But it's not a point where two of the constraints cross, so
to me, it's not what I would call a 'corner'.
C). (8, 0)
Definitely not a corner, no matter how you define a 'corner'.
This point is deep inside the non-feasible zone, and it doesn't
touch any point in the feasible zone.
So tome, this looks like probably the best answer.
D). (5, 3)
This is definitely a corner. It's the point of intersection (the solution)
of the two equations that are the first two constraints.
The feasible region is a triangle.
The three vertices of the triangle are (0,8) (choice-A),
(0,-7) (not a choice), and (5,3) (choice-D) .
region is a triangle
The answers that you put are right.
Good job!
