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il63 [147K]
3 years ago
15

I need help on this problem is the answer A

Mathematics
1 answer:
vladimir1956 [14]3 years ago
3 0
Well, I'm not completely sure, because I don't know the formal definition
of "corner" in this work.  It may not be how I picture a 'corner'.

Here's what I can tell you about the choices:

A).  (0, 8)
This is definitely a corner of the feasible region.
It's the point where the first and third constraints cross.
So it's not the answer.

B).  (3.5, 0)
This is ON the boundary line between the feasible and non-feasible
regions. But it's not a point where two of the constraints cross, so
to me, it's not what I would call a 'corner'.

C).  (8, 0)
Definitely not a corner, no matter how you define a 'corner'.
This point is deep inside the non-feasible zone, and it doesn't
touch any point in the feasible zone. 
So tome, this looks like probably the best answer.

D).  (5, 3)
This is definitely a corner.  It's the point of intersection (the solution)
of the two equations that are the first two constraints. 

The feasible region is a triangle.
The three vertices of the triangle are  (0,8) (choice-A), 
(0,-7) (not a choice),  and  (5,3) (choice-D) .
region is a triangle

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Factor the expression given below. Write each factor as a polynomial in
bezimeni [28]

Answer:

3(343=72y)

Step-by-step explanation:

343x3=1029

1029+216y

both divisible by 3

3(343=72y)

6 0
3 years ago
Please show all work!! this is algebra.
Mnenie [13.5K]
Franco:
3x+2y=19
Caryl:
2x+4y=24

now use elimination

-2(3x+2y=19)
1(2x+4y=24)
=
-6x-4y=-38
2x+4y=24
add them together
which equals -4x=-14
divide both sides by -4
-4x/-4=-14/-4
x=7/2


we found x, so we subsitute it into the the original equation

3x+2y=19
3(7/2)2y=19
2y+21/2=19
-21/2 -21/2
2y=17/2
divide by 2 on both sides
2y/2= 17/2/2
y=17/4

so x= 7/2 and y= 17/4


8 0
1 year ago
Does each function describe exponential growth or decay?
zhannawk [14.2K]

Hey Jinx :)

------------------------------------------------

Note that a decay has a rate between 0 and 1, and a growth as a rate of 1 or higher.

y = 1/2(1 + 0.03)^t → y = 1/2(1.03)^t (Rate is more then 0) GROWTH

y = 0.3(0.95)^t → (Rate is between 0 and 1) DECAY

y = ((1+0.03)^1/2)^2t → y = y = 1.014^2t (Rate is more then 0) GROWTH

y = 200(0.73)^t → (Rate is between 0 and 1) DECAY

y = 4(1/4)^t → (Rate is between 0 and 1) DECAY

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Hope This Helped! Good Luck!

4 0
3 years ago
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3 years ago
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