$\frac1x+\frac56=\frac{13}{12}\ \ \ \ |\cdot12\\ 12\cdot\frac1x+12\cdot\frac56=12\cdot\frac{13}{12}\\ \frac{12}x+\frac{60}6=13\\ \frac{12}x+10=13\ \to \ \frac{12}x=3\ \to \ \boxed{x=4}$

4 0

3 years ago

Read 2 more answers

What number multiplied by itself 3 times equals-343

professor190 [17]

343*3=1029 this is the answer

7 0

3 years ago

A study is conducted to determine if a newly designed text book is more helpful to learning the material than the old edition. T

Oksanka [162]

Answer:

The null and alternative hypotheses are:

$H_{0}:\mu=75$

$H_{a} : \mu>75$

Under the null hypothesis, the test statistic is:

$t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }$

Where:

$\bar{x} =83$ is the sample mean

$s=9.8206$ is the sample standard deviation

$n=10$ is the sample size

$\therefore t= \frac{83-75}{\frac{9.8206}{\sqrt{10}} }$

$=2.58$

Now, we can find the right tailed t critical value at 0.01 significance level for df = n-1 = 10 - 1 = 9 using the t distribution table. The t critical value is given below:

$t_{critical} =2.821$

Since the test statistic is less than the t critical value, we therefore, fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the people do better with the new edition.

7 0

3 years ago