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2 years ago

What is the slope of this line?

Mathematics

1 answer:

Anvisha [2.4K]2 years ago

5 0

(-4,5),(0,6)

slope = rise/run
tip... you have to crawl (run) before you run (rise) .

you can use the slope formula
$\frac{5 - 6}{ - 4 - 0} = \frac{ - 1}{ - 4} = \frac{1}{4}$
1/4

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7717 as a percentage

Georgia [21]

The percentage of 7717 is 129.8%

8 0

3 years ago

A storage space in a basement is in the shape of a rectangular prisim. The hieght of the storage space is 5 feet. The length is

Greeley [361]

Answer:

length is 28.86ft

width= 4.12ft

Step-by-step explanation:

<h2>This problem bothers on the mensuration of solid shapes, a rectangular prism.</h2>

The storage space takes the shape of a rectangular prism, and we are required to find the width and length of the storage space.

let the width of the basement be "w"

Given data

volume v= $595ft^{3}$

length l = $7w ft$

width w= $w$

height h= $5 ft$

We know that the expression for the volume of a rectangular prism is

$volume= length * width* height$

substituting our data we have to find "w"

$595= 7w*w*5\\595=7w^{2}*5\\ 595= 35w^{2} \\$

dividing both sides by 35 we have

$w^{2}= \frac{595}{35\\} \\w^{2}= 17\\$

find the square root of both sides we have

$w=\sqrt{17} \\w= 4.12$

since we know that length= 7w and width = w , we can substitute our value for w and find the length and width

$length= 7*4.12= 28.86ft\\width = 4.12ft$

6 0

3 years ago

Please help me with this geometry question. x and pr needed ao basically like this x=(answer), PR=(answer). Thank you

Dennis_Churaev [7]

Answer:

x = -1, PR = 38.

Step-by-step explanation:

As Q is the midpoint of PR

PQ = QR

6x + 25 = 16 - 3x

9x = -9

x = -1.

= 6x + 25 + 16 - 3x

= 6(-1) + 25 + 16 - 3(-1)

= -6 + 25 + 16 + 3

= 38.

7 0

2 years ago

Answer this question! i am having some trouble in khan..

anzhelika [568]

The correct answer is 33 days

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2 years ago

Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$

4 0

1 year ago