Question

can anyone help me with this? also, take note that the word “ hence ” requires the use of the previous solution used in the earlier parts.

Answer 1

(a) x = +/- 3 (or 0)

-Because x is being squared, it does not matter if it is positive or negative, as when any number is squared the product is always positive.

3x^2 - 9x = 0

3x(x - 3) = 0

x = 0

x = +/- 3

(b) x = 6, -4

x^2 - 2x - 24 = 0

(x - 6)(x + 4) = 0

x = 6

x = -4

(c) y = 8, -2

(y - 2)^2 - 2(y - 2) - 24 = 0

(y^2 - 4y + 4) - 2y + 4 - 24 = 0

y^2 - 6y - 16 = 0

(y - 8)(y + 2) = 0

y = 8

y = -2

Hope this helps! :)