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azamat
3 years ago
14

If a classmate is trying to estimate 42% of $122. Explain how your classmate should solve the problem. In a 6th graders work

Mathematics
2 answers:
horsena [70]3 years ago
8 0
Multiply 42% time 122 and your answer is 51.24
Bess [88]3 years ago
3 0
Well I say 42/100 × 122. Then when you reduce it you get 42/25 × 31. You will get an answer of 1301/25. But it is not over yet; when you divide 1301 with 25 and get the answer of 52.04. Now you must round it if to then nearest tenth place. That will be 52.0. Now you can round it to the nearest whole number or you can do that when you get your decimal answer in the first place. Anyway, when you round it to the nearest whole number you get 52 as your answer.
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A cylinder with a height of 12 cm is inscribed in a sphere with a radius of 10 cm. Find the lateral area of the cylinder. Answer
zalisa [80]

Answer:

256π

Step-by-step explanation:

Given that:

The height of the cylinder: 12 cm

The radius of the sphere : 10

Let r is the radius of the cylinder, use Pytagon

10² = r² + 6²

<=> r²  = 10² - 6²  = 64

<=> r = 8

Hence,  the lateral area of the cylinder

L= 2πrh

= 2π8*16

= 256π

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3 years ago
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5 0
2 years ago
The graph shows the relationship between the number of pounds of oranges purchased and the total oost of oranges what is the cos
Ymorist [56]

Answer:

1

Step-by-step explanation:

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5 0
3 years ago
Suppose f(x) = 12x – 1,400 and g(x) = 12x – 1,535. Describe the transformation of the graph of f to the graph of g. Group of ans
m_a_m_a [10]
The graph is translates down 135 units, because you can see how the y-intercept decreased by 135 units from f(x) to g(x).
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3 years ago
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morpeh [17]

Answer:

{ \sf{( \sec \theta -  \csc \theta)(1 +  \tan \theta +  \cot \theta) }} \\  = { \sf{( \sec \theta +  \tan \theta \sec \theta +  \cot  \theta \sec  \theta) - ( \csc  \theta -   \csc \theta \tan  \theta -  \csc \theta \cot  \theta)}} \\  = { \sf{( \sec \theta +  \sec \theta \tan  \theta +  \csc  \theta) - (  \csc  \theta -  \sec \theta -  \csc  \theta \cot   \theta)}} \\  = { \sf{ \sec  \theta \tan  \theta +  \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}

3 0
2 years ago
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