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3 years ago

Drawing A Red Tile From A Bag And Then Drawing A Green Tile After Replacing The First Tile. Dependent Or Independent?

Mathematics

1 answer:

balandron [24]3 years ago

5 0

Answer:

Independent

Step-by-step explanation:

with replacement the total number of tiles will always remain the same,i.e the sample size will not be changed. so the events are independent.

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Sean sold half of his comics to buy a game. Later, he bought 7 new comics. How many did he start with if he now has 20:

Solnce55 [7]

Answer:

Step-by-step explanation:

20-7= 13 (half his comics) 13+13=26

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3 years ago

4 value of 546 210 in words

FrozenT [24]

Five hinder and fourty six and two hundred and ten

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3 years ago

Use FTC2 to find the derivative

labwork [276]

Answer: 17/2 = 8.5

Ok done. Thank to me :>

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2 years ago

Select the basic integration formula you can use to find the indefinite integral.

kondaur [170]

Answer:

$\int \dfrac{du}{u}=\log|u|+C$

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$

Step-by-step explanation:

$\int \dfrac{du}{u}=\log|u|+C$ $[\because \int \dfrac{dx}{x}=\log |x|+C]$

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$ $[\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]$

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$ $[\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]$

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3 years ago

Choose any positive integer. Powers of two here are not very interesting, so choose something else. If the number you have chose

Yakvenalex [24]

Answer:

Step-by-step explanation:

Let the integer be 6 for even and 7 for odd (say)

For 6, we divide by 2, now get 3. Now we multiply by 3 and add 1 to get 10. Now since 10 is even divide by 5, now multiply by 3 and add 1 to get 16. Now divide by 2 again by 2 again by 2 again by 2 till we get rid of even numbers.

The result is 1, so multiply by 3 and add 1 we get 4 now divide 2 times by 2 to get 1, thus this result now again repeats after 2 times.

Say if we select off number 3, multiply by 3 and add 1 to get 10 now divide by 5, now repeat the same process as above for 5 until we get 1 and it gets repeated every third time.

Thus whether odd or even after some processes, we get 1 and the process again and again returns to 1.

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3 years ago